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3 years ago

(sec 12A - 1)/(sec 6A -1) = tan 12A / tan 3A

Mathematics

1 answer:

Ganezh [65]3 years ago

5 0

Can I use dis... do u know how to use dis?

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Can someone please help me factor and write the equations for these two problems ?

prisoha [69]

Answer:

Step-by-step explanation:

Asymptotes 3

g(x) = $\frac{3x}{x^2-3x-10}$

Factors of denominator will be,

x² - 3x - 10 = x² - 5x + 2x - 10

= x(x - 5) + 2(x - 5)

= (x + 2)(x - 5)

Therefore, factored form of g(x) will be,

g(x) = $\frac{3x}{(x + 2)(x - 5)}$

Asymptotes 4

h(x) = $\frac{(x-5)}{x^{2} + 14x + 40}$

= $\frac{x-5}{x^{2}+10x+4x+40}$

= $\frac{x-5}{x(x+10)+4(x+10)}$

= $\frac{x-5}{(x+10)(x+4)}$

5 0

3 years ago

Which expression is equal to 6^4? A: 10 B: 24 C: 4^6 D: 6•6•6•6

slega [8]

The answer to ur question is d: 6x6x6x6

8 0

3 years ago

Read 2 more answers

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uranmaximum [27]

Answer: 10,000

Step-by-step explanation:

5 0

3 years ago

A chemical company makes two brands of antifreeze. The first brand is 65% pure antifreeze, and the second brand is 90% pure anti

Murrr4er [49]

With amounts measured in gallons, let

x = amount of 65% antifreeze

y = amount of 90% antifreeze

1 gal of the 65% brand contains 0.65 gal of pure antifreeze; x gal would contain 0.65x gal. Similarly, y gal of the 90% brand contains 0.90y gal of pure antifreeze.

To obtain 120 gal of 80% antifreeze solution (which contains 0.80•120 = 96 gal of pure antifreeze), we must have

x + y = 120 … … … … … [total volume of antifreeze solution]

0.65x + 0.90y = 96 … [total volume of pure antifreeze]

Solve the first equation for y :

y = 120 - x

Substitute this into the second equation and solve for x :

0.65x + 0.90 (120 - x) = 96

0.65x + 108 - 0.90x = 96

0.25x = 12

x = 48

Solve for y :

y = 120 - 48

y = 72

6 0

2 years ago

What’s is the slope of the lin

Lady bird [3.3K]

Answer:

1/3

Step-by-step explanation:

Method 1.

slope = rise/run

Rise is vertical distance.

Run is horizontal distance.

Find two points that are easy to read (on grid intersections):

(2, -1) and (5, 0).

Start at (2, 1). You need to go to (5, 0) by moving only vertically and horizontally. Go up 1 unit. That is a rise of 1. Now go right 3 units. That is a run of 3.

rise = 1

run = 3

slope = rise/run = 1/3

Method 2.

Use the slope formula and two points on the line.

$slope = m = \dfrac{y_2 - y_1}{x_2 - x_1}$