Answer:
Given, two numbers 56 and 57 we need to find out the numbers lie between the squares of the given numbers.
Now, we have numbers lying between the square of n and (n + 1) is 2n
⇒ Numbers between squares of 56 and (56 + 1) = 2 × 56 = 112
Hence, 112 numbers lies between the square of the given numbers.
Answer:
C-2
Step-by-step explanation:
Answer:
Step-by-step explanation:
Okay, so hopefully my crude diagram helps you visualize the problem. When in doubt, always draw a picture.
All I did was graph the points and formed a line.
Slope: It's going to be 0 because it doesn't change at all (no different y values)
(y2-y1)/(x2-x1) = (6-6) / (4-2) = 0/2 = 0
Y intercept is where the line crosses the y axis- this is also where x=0 (find it in your chart!)
Equation is y= 6; I don't know how to explain this, but trust me, it's right
Answer:
20 ; $135 ; service charge for 3 hours spent is $135
Step-by-step explanation:
Given that :
Service fee equation model :
C(h)= 75 + 20h
C = total cost of the service call
h = number of hours the plumber spends working on the problem
The charge per hour is the gradient or slope of the linear equation. From the equation, the slope is of the equation is related to bx from. The general form of a linear equation where b = gradient or slope(charge per hour) and x = number of hours
bx = 20h
b = 20
Charge per hour = 20
C(3) = 75 + 20(3)
75 + 60 = 135
This means that total service call charge for a plumber who spends three hours fixing a problem is $135
king jon un
Step-by-step explanation:
