<img src="https://tex.z-dn.net/?f=6%5E%7B0%7D" id="TexFormula1" title="6^{0}" alt="6^{0}" align="absmiddle" class="latex-formula

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Feliz [49]

3 years ago

"> rewrite as an equivalent expression without the use of negative or zero exponents

Mathematics

1 answer:

Mumz [18]3 years ago

4 0

1. Anything to the zero power is 1.

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Find m∠U.<br> Write your answer as an integer or as a decimal rounded to the nearest tenth.

olga2289 [7]

Answer:

Answer:

50.2

Step-by-step explanation:

$ut = \sqrt{ {6}^{2} + {5}^{2} } \\ \sqrt{36 + 25} \\ \sqrt{61 } \\ using \: cosine \: rule \\ cos \: u = \frac{ {5}^{2} + 61 - 36 }{2 \times 5 \times \sqrt{61} } \\ \\ = \frac{25 + 61 - 36}{78} \\ \\ = \frac{50}{78 } \\ \cos \: u = 0.64 \\ m∠U. = 50.2$

7 0

1 year ago

If u, v, and w are nonzero vectors in r 2 , is w a linear combination of u and v?

Tju [1.3M]

Not necessarily. $\mathbf u$ and $\mathbf v$ may be linearly dependent, so that their span forms a subspace of $\mathbb R^2$ that does not contain every vector in $\mathbb R^2$ .

For example, we could have $\mathbf u=(0,1)$ and $\mathbf v=(0,-1)$ . Any vector $\mathbf w$ of the form $(r,0)$ , where $r\neq0$ , is impossible to obtain as a linear combination of these $\mathbf u$ and $\mathbf v$ , since

$c_1\mathbf u+c_2\mathbf v=(0,c_1)+(0,-c_2)=(0,c_1-c_2)\neq(r,0)$

unless $r=0$ and $c_1=c_2$ .

8 0

3 years ago

From 5 employees at a company, a group of 3 employees will be chosen to work on a project. How many different groups of 3 employ

Andrei [34K]

Hello,

aPb=b*(b-1)*(b-2)*....*(b-a+1) / a!

3P5=5*4*3/(3*2*1)=10

If we name the number of the employers 1,2,3,4,5

Here are the choices:

123,124,125,134,135,145,234,235,245,345 (total 10 choices)

8 0

2 years ago

Read 2 more answers

4x3x8x7x9x3x6x7x7x3x9x7x2x3x6x9x9x2x4x2x3x2x8 = ????⇒∈<br><br> pls answer ill mark brainly

Virty [35]

Answer:

564,457,073,983,488......

6 0

2 years ago

SAT scores probability 1

fredd [130]

Answer:

a. 81.5%

Step-by-step explanation:

The z-score for 400 is ...

Z = (X -μ)/σ = (400 -500)/100 = -1

The z-score for 700 is ...

Z = (700 -500)/100 = 2

The empirical rule tells you that 68% of the distribution is within ±1σ of the mean, and 95% is within ±2σ of the mean. Half of that first number is in the range Z = -1 to 0, and half that second number is in the range Z = 0 to +2. So, the probability you want is ...

(1/2)(68%) + (1/2)(95%) = 81.5% . . . . matches choice A

6 0

3 years ago