<img src="https://tex.z-dn.net/?f=6%5E%7B0%7D" id="TexFormula1" title="6^{0}" alt="6^{0}" align="absmiddle" class="latex-formula

X+(x+2)+(x+4)=396, x+x+x+6=396, 3x+6=396, 3x=396-6, 3x=390, x=130, x+2=130+2=132, x+4=130+4=134. The three consecutive even integers are 130, 132, 134

8 0

3 years ago

Laundry detergent boxes are filled according to an approximately Normal distribution with mean 34.15 ounces and standard deviati

Leno4ka [110]

Using the normal distribution, it is found that there is a 0.0668 = 6.68% probability a randomly selected box has less than the 34 ounces of advertised weight.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

$\mu = 34.15, \sigma = 0.1$ .

The probability a randomly selected box has less than the 34 ounces of advertised weight is the <u>p-value of Z when X = 34</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{34 - 34.15}{0.1}$

Z = -1.5

Z = -1.5 has a p-value of 0.0668.

0.0668 = 6.68% probability a randomly selected box has less than the 34 ounces of advertised weight.

More can be learned about the normal distribution at brainly.com/question/24537145

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7 0

2 years ago