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Ede4ka [16]
3 years ago
5

The following data points represent the yearly salaries of high school cheerleading coaches in Dakota county (in thousands of do

llars). 41 38 36 57 43
Mathematics
1 answer:
jenyasd209 [6]3 years ago
5 0

Answer:

5.6 thousand

Step-by-step explanation:

To find the mean absolute deviation (MAD), first find the mean (or average).

μ = (41 + 38 + 36 + 57 + 43) / 5

μ = 43

Next, subtract the mean from each value and take the absolute value.

|41 − 43| = 2

|38 − 43| = 5

|36 − 43| = 7

|57 − 43| = 14

|43 − 43| = 0

Sum the results and divide by the number of animals.

MAD = (2 + 5 + 7 + 14 + 0) / 5

MAD = 5.6

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Sec x is equal to 1/cosx, cot x is equal to cosx/sinx. cos x cancels, and you are left with 1/sinx. this is equal to cscx. Cosecant is : hypotenuse / opposite, so the answer is **D**
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3 years ago
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When 5 is added to a set of 3 numbers the mean increases to 4.6. What was the mean of the original 3 numbers?
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<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷  Multiply 4.6 by 4 to get the sum of the numbers after 5 was added:

4.6 x 4 = 18.4

^ This is the new total

Subtract 5 from this:

18.4 - 5 = 13.4

Divide this value by 3 to get the original mean:

13.4/3 = 67/15

<h3><u>✽</u></h3>

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7 0
3 years ago
Answer the question attached:<br><br> (I need this ASAP)
Illusion [34]

Answer:

A≈534.07

Step-by-step explanation:

A=2πrh+2πr^2

6 0
3 years ago
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7 divided by somethings equal 7.35
Dmitriy789 [7]
Let's translate it into an equation and then solve...

7/x = 7.35
x * 7/x = 7.35 * x
7 = 7.35x
7/7.35 = x
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3 years ago
If dy/dx = x(y-1), find the equation of the tangent line at x=-2 with f(-2)=3
Lapatulllka [165]

Answer:

The equation of the tangent line passing through the point (-2,3) is

 4 x + y +5 =0

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given that the slope of the tangent</em>

<em>              </em>m = \frac{dy}{dx} = x(y-1)<em></em>

<em>              m = -2( 3-1) = -4</em>

<em>Given point x = -2</em>

<em>          y = f(-2) =3</em>

<em>∴The given point ( x₁ , y₁) = ( -2 ,3)</em>

<u><em>Step(ii):-</em></u>

The equation of the tangent line passing through the point (-2,3)

y - y_{1} = m(x-x_{1} )

y -3 = -4(x-(-2))

y -3 = -4( x+2)

y-3 = -4x -8

4x + y -3+8=0

4x +y +5=0

<u><em>Step(iii):-</em></u>

<em>The equation of the tangent line passing through the point (-2,3) is</em>

<em>   4 x + y +5 =0</em>

<em></em>

3 0
2 years ago
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