The following data points represent the yearly salaries of high school cheerleading coaches in Dakota county (in thousands of do
1 answer:
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Answer:
Step-by-step explanation:
Given that the height in inches, of a randomly chosen American woman is a normal random variable with mean μ = 64 and variance 2 = 7.84.
X is N(64, 2.8)
Or Z =
a) the probability that the height of a randomly chosen woman is between 59.8 and 68.2 inches.
b)
c) For 4 women to be height 260 inches is equivalent to
4x will be normal with mean (64*4) and std dev (2.8*4)
4x is N(266, 11.2)
d) Z is N(0,1)
E(Z19) =
since normal distribution is maximum only between 3 std deviations form the mean on either side.
Answer:
a. 54.05 Mpbs.
b. 2.745... standard deviations.
c. The z-score is 2.745....
d. The carrier's highest data speed is significantly high.
Step-by-step explanation:
a. The difference between the highest measured data speed and the mean is 72.6 - 18.55 = 54.05 Mbps.
b. The amount of standard deviations of 54.05 Mbps is equal to this value divided by the standard deviations, so we yield standard deviations.
c. The z-score is equal to the difference between the mean and a data point in standard deviations, so the z-score is 2.745....
d. 2.745... is not between -2 and 2, so the carrier's highest data speed is not insignificant - so it's significantly high.