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3 years ago

Is each pair of systems equivalent? Explain.

1 answer:

8 0

No. 3x - 4y = -6 is not equal to 6x - 8y = 12. If you multiplied the first equation by 2, it would be 6x - 8y = -12, not 6x - 8y = 12. As for the second pair, if you multiply 2x + 5y = 1 by 3, it would be 6x + 15 = 3. So the second pair are equal.

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Santa's elves are selling

Andreas93 [3]

cost of one peppermint cookies = $ 0.6

cost of one cinnamon sugar cookies = $ 0.3

<h3><u>Solution:</u></h3>

Let "p" be the cost of one peppermint cookies

Let "c" be the cost of one cinnamon sugar cookies

<u><em>To find: cost of each cookie</em></u>

<h3><u><em>On the first day, they sold 120 peppermint cookies and 30 cinnamon sugar cookies for a total of $81</em></u></h3>

We can frame a equation as:

120 peppermint cookies x cost of one peppermint cookies + 30 cinnamon sugar cookies x cost of one cinnamon sugar cookies = $ 81

$120 \times p + 30 \times c = 81$

120p + 30c = 81 --------- eqn 1

<h3><u><em>The next day they made $60 by selling 70 peppermint cookies and 60 cinnamon sugar cookies</em></u></h3>

70 peppermint cookies x cost of one peppermint cookies + 60 cinnamon sugar cookies x cost of one cinnamon sugar cookies = $ 60

$70 \times p + 60 \times c = 60$

70p + 60c = 60 --------- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "p" and "c"

Multiply eqn 1 by 2

240p + 60c = 162 --- eqn 3

Subtract eqn 2 from eqn 3

240p + 60c = 162

70p + 60c = 60

(-) -------------------------

170p = 102

Substitute p = 0.6 in eqn 1

120p + 30c = 81

120(0.6) + 30c = 81

72 + 30c = 81

30c = 9

<u><em>Summarizing the results:</em></u>

<em>cost of one peppermint cookies = $ 0.6</em>

<em>cost of one cinnamon sugar cookies = $ 0.3</em>

6 0

3 years ago

Zachary has been trying to work on an essay for almost three hours, but he can't seem to focus for more than 15 or 20 minutes at

Julli [10]

Well he should go somewhere he can be alone

5 0

3 years ago

I need help on this question plz

Oduvanchick [21]

i think all of them can be shown on a catergrorical graph

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The value of (3^0+2^0) * 5^0<br><br>1<br>25<br>0<br>2

Ksivusya [100]

(3^0+2^0)(5^0)

=(3^0+2^0)(5^0)

=(3^0)(5^0)+(2^0)(5^0)

= 1 + 1

= 2

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Jeremy checked the mail at 11:00 a.m. for one week, and it was never there. He then checked the mail at noon for one week, and i

Simora [160]

C,

because he checks at 12:00 on the dot or that's what they're implying, so it can't be D

and the mail is always there at noon, so b is out of the question,

and a, well common sense it

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