To find the vertex of the parabola, we need to write it in a vertex form.
y=x² - 8x +12
1) complete the square
y=
x² - 8x +12
y =
x² -2*4x + 4² - 4² +12
y=
(x-4)² -16 +12
2) calculate and write a vertex
y=
(x-4)² -16 +12
y=
(x-4)² - 4
(x-4) ----- x- coordinate of the vertex x=4
y=(x-4)²
- 4 -------y- coordinate of the vertex y = - 4 Vertex is (4, -4).
Answer is (4, -4). No correct answer is given in choices.
Answer:
-6 = x
Step-by-step explanation:
2x-8=4(x+1)
Distribute
2x -8 = 4x+4
Subtract 2x
2x-8-2x = 4x-2x+4
-8 = 2x+4
Subtract 4
-8-4 = 2x+4-4
-12 = 2x
Divide by 2
-12/2 = 2x/2
-6 = x
Answer:
c=2.4a+2537.8
a=-2.5/6c+1057.4
Step-by-step explanation:
solve for c:
2.50c+6a=6344.50
-6a -6a
2.50c=-6a+6344.50
/2.50 /2.50 /2.50
c=2.4a+2537.8
solve for a:
2.50c+6a=6344.50
-2.5c -2.5c
6a=-2.5c+6344.50
/6 /6 /6
a=-2.5/6c+1057.4
Answer:
1/2
2 is the total parts. you can visualise it as a circle or another form of a diagram. so theres 2 parts. 1 might mean one segmented is shaded or cut depending on the context