Do recall that squaring and the *radical sign* cancel each other out... like so:(

)

= a
When you put it that way, it isn't enough :P
(

)

= a
(

)

=?
so you start with
(

)

=

8x+1=25 <-- subtract 1 to both sides
8x=24 <- divide 8 to both sides
x= 3
To find out if it's an extraneous solution ask yourself: It mustn't result in a radical that I like to call... 'illegal'. Plug it into the radicand 8x+1 and make sure you get something that is not a negative number.... so, DO you get a negative number when you plug in x = 3 into the radicand?
(extraneous solution is a invalid solution)
x=3 not extraneous
Answer:
I think your answer would be 12x - 2
If this is wrong then im sorry
P = 5
I am not sure if this is correct. However, P is used to represent the addresses and there are 5 addresses. Therefore p = 5.
Answer:
J(-5,2), A(-5,4), and N(-1,1)
Step-by-step explanation: