Yes, absolutely! You have correctly identified a good line of best fit and found a point that matches with the 450 thousand. Good job!
Answer:
<em>Any width less than 3 feet</em>
Step-by-step explanation:
<u>Inequalities</u>
The garden plot will have an area of less than 18 square feet. If L is the length of the garden plot and W is the width, the area is calculated by:
A = L.W
The first condition can be written as follows:
LW < 18
The length should be 3 feet longer than the width, thus:
L = W + 3
Substituting in the inequality:
(W + 3)W < 18
Operating and rearranging:

Factoring:
(W-3)(W+6)<0
Since W must be positive, the only restriction comes from:
W - 3 < 0
Or, equivalently:
W < 3
Since:
L = W + 3
W = L - 3
This means:
L - 3 < 3
L < 6
The width should be less than 3 feet and therefore the length will be less than 6 feet.
If the measures are whole numbers, the possible dimensions of the garden plot are:
W = 1 ft, L = 4 ft
W = 2 ft, L = 5 ft
Another solution would be (for non-integer numbers):
W = 2.5 ft, L = 5.5 ft
There are infinitely many possible combinations for W and L as real numbers.
Answer:
Depth of the rain gutter is 8 inches
Step-by-step explanation:
Let’s assume ‘x’ is the depth of the rain gutter
Then the width of the rain gutter can be written as 16 - 2x
Cross sectional area
A = depth x width
Substitute values
A = x*(16 - 2x)
A = 16x – 2x^2
Now according to axis of symmetry for maximum area x = -b/2a
x = -16/2*(-2)
x = 4 inches depth of rain gutter, substitute the value of x to get
Width of rain gutter 16 – 2(4) = 8 inches
Area of the rain gutter for maximum water flow
A = 4 * 8
A = 32 square inch.