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2 years ago

5

The equation for picture D is 13 4/5 = w + 3 4/5. What is the solution? Write the number answer only. Please do not write the va

riable with it

1 answer:

aksik [14]2 years ago

4 0

Answer:

13 4/5 = 10 + 3 4/5

Step-by-step explanation:

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2 years ago

Test 1. Give the appropriate factoring technique and factors of the following polynomials.

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2 years ago

Solve for equation √-5p=√24-p

blsea [12.9K]

Answer:

Step-by-step explanation:

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p2-5p-24=0

Two solutions were found :

p = 8

p = -3

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "p2" was replaced by "p^2".

Step by step solution :

Step 1 :

Trying to factor by splitting the middle term

1.1 Factoring p2-5p-24

The first term is, p2 its coefficient is 1 .

The middle term is, -5p its coefficient is -5 .

The last term, "the constant", is -24

Step-1 : Multiply the coefficient of the first term by the constant 1 • -24 = -24

Step-2 : Find two factors of -24 whose sum equals the coefficient of the middle term, which is -5 .

-24 + 1 = -23

-12 + 2 = -10

-8 + 3 = -5 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -8 and 3

p2 - 8p + 3p - 24

Step-4 : Add up the first 2 terms, pulling out like factors :

p • (p-8)

Add up the last 2 terms, pulling out common factors :

3 • (p-8)

Step-5 : Add up the four terms of step 4 :

(p+3) • (p-8)

Which is the desired factorization

Equation at the end of step 1 :

(p + 3) • (p - 8) = 0

Step 2 :

Theory - Roots of a product :

2.1 A product of several terms equals zero.

When a product of two or more terms equals zero, then at least one of the terms must be zero.

We shall now solve each term = 0 separately

In other words, we are going to solve as many equations as there are terms in the product

Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation :

2.2 Solve : p+3 = 0

Subtract 3 from both sides of the equation :

p = -3

Solving a Single Variable Equation :

2.3 Solve : p-8 = 0

Add 8 to both sides of the equation :

p = 8

8 0

3 years ago

Consider h(x)=x^2+8+15. identify its vertex and y-intercept.

OleMash [197]

Answer:

Vertex: (-4, -1)

Y-intercept: (0, 15)

Step-by-step explanation:

Given the quaratic function, h(x) = x² + 8x + 15:

In order to determine the vertex of the given function, we can use the formula, $[x = \frac{-b}{2a}, h(\frac{-b}{2a})]$ .

<h3>Use the equation: $[x = \frac{-b}{2a}, h(\frac{-b}{2a})]$ </h3>

In the quadratic function, h(x) = x² + 8x + 15, where:

a = 1, b = 8, and c = 15:

Substitute the given values for <em>a</em> and <em>b</em> into the equation to solve for the x-coordinate of the vertex.

$x = \frac{-b}{2a}$

$x = \frac{-8}{2(1)}$

x = -4

Subsitute the value of the x-coordinate into the given function to solve for the <u>y-coordinate of the vertex</u>:

h(x) = x² + 8x + 15

h(-4) = (-4)² + 8(-4) + 15

h(-4) = 16 - 32 + 15

h(-4) = -1

Therefore, the vertex of the given function is (-4, -1).

<h3>Solve for the Y-intercept:</h3>

The <u>y-intercept</u> is the point on the graph where it crosse the y-axis. In order to find the y-intercept of the function, set x = 0, and solve for the y-intercept:

h(x) = x² + 8x + 15

h(0) = (0)² + 8(0) + 15

h(0) = 0 + 0 + 15

h(0) = 15

Therefore, the y-intercept of the quadratic function is (0, 15).

5 0

2 years ago