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Dimas [21]
2 years ago
11

If Andrew spends 90 cents per litre and he goes 100km within 8.8 litres how far will $20 get him

Mathematics
1 answer:
dalvyx [7]2 years ago
6 0

It will get him to 252.5km

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Find the slope between points (4,-5) and (5,-1)
Yuki888 [10]

Answer:

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PLEASE HELP SUPER EASY IM JUST STUPID
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Which expression is equivalent to square root 55x^7y6/11x^11y^8
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Answer:

\large\boxed{\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\dfrac{\sqrt5}{x^2y}}

Step-by-step explanation:

\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\sqrt{\dfrac{55}{11}\cdot\dfrac{x^7}{x^{11}}\cdot\dfrac{y^6}{y^8}}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\=\sqrt{5x^{7-11}y^{6-8}}=\sqrt{5x^{-4}y^{-2}}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt5\cdot\sqrt{x^{-4}}\cdot\sqrt{y^{-2}}=\sqrt5\cdot\sqrt{x^{(-2)(2)}}\cdot\sqrt{y^{(-1)(2)}}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt5\cdot\sqrt{(x^{-2})^2}\cdot\sqrt{(y^{-1})^2}\qquad\text{use}\ \sqrt{a^2}=a

=\sqrt5\cdot x^{-2}\cdot y^{-1}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\to a^{-1}=\dfrac{1}{a}\\\\=\sqrt5\cdot\dfrac{1}{x^2}\cdot\dfrac{1}{y}=\dfrac{\sqrt5}{x^2y}

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How many tenths are in 4/5?<br> (Show how to do it too!)
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7 0
3 years ago
How many terms are in the simplified expression -3x 2 + 2y 2 + 5xy - 2y + 5x 2 - 3y 2
Vilka [71]

there are 6 terms in the simplified expression


4 0
3 years ago
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