801= 8.01×10^2
0.0801= 8.01×10^-2
8,010,000= 8.01×10^6
.00000801=8.01×10^-6
If the exponent of the 10^(A NUMBER) part is positive, then it is greater than one.
Answer:
Danny wants to buy some Pop Tarts to smoke. His father gives him $300 (he likes to smoke them too) but says to only spend 65% of it. How much money (exlcuding taxes) will Danny have to give back to his Dad?
Step-by-step explanation:
300*.65= 195.
300-195=105
Answer: P(B|G) = 3/5 = 0.6
the probability that the guest is the friend of bride, P(bride | groom) is 0.6
Complete Question:
The usher at a wedding asked each of the 80 guests whether they werea friend of the bride or of the groom. The results are: 59 for Bride, 50 for Groom, 30 for both. Given that the randomly chosen guest is the friend of groom, what is the probability that the guest is the friend of bride, P (bride | groom)
Step-by-step explanation:
The conditional probability P(B|G), which is the probability that a guest selected at random who is a friend of the groom is a friend of the bride can be written as;
P(B|G) = P(B∩G)/P(G)
P(G) the probability that a guest selected at random is a friend of the groom.
P(G) = number of groom's friends/total number of guests sample
P(G) = 50/80
P(B∩G) = the probability that a guest selected at random is a friend is a friend of both the bride and the groom.
P(B∩G) = number of guests that are friends of both/total number of sample guest
P(B∩G) = 30/80
Therefore,
P(B|G) = (30/80)/(50/80) = 30/50
P(B|G) = 3/5 = 0.6
Better yet, let y = 6 and solve for x.
6 = x^2 –2x + 5
Now solve for x.
