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nikklg [1K]
3 years ago
15

What is the length of line segment EF?

Mathematics
2 answers:
luda_lava [24]3 years ago
8 0
The answer to this problem is...3.6
rosijanka [135]3 years ago
3 0

Answer:

EF = 3.6 is the answer.

Step-by-step explanation:

In the given picture coordinates of the endpoints of EF has been given and we have to calculate the length of the segment EF.

As we know when coordinates of two points are given and we have to calculate the distance between them we use the formula

Distance EF = √[(x - x')²+(y - y')²]

Here (x, y) and (x', y') are (-3, 1) and (-1, -2).

So distance EF = √(-3+1)²+(1+2)² =√(-2)²+(3)² = √(4 + 9) = √13

EF = 3.60

So the answer is 3.6

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denis-greek [22]

Answer:

\bullet \ \large\text{The mean in period 2 is higher than the mean in period 1.}

Step-by-step explanation:

<u><em>the mean in period</em></u> 1 :

(2.3+2.1+2.2+2.2+2.2+2.1+2.4+2.5+2.2+2.0+1.9+1.9+2.1+2.2+2.3)÷15=21.733...

<u><em>the mean in period</em></u> 2 :

(2.3+2.1+3.3+1.5+3.6+1.6+3.0+1.1+4.7+2.1+2.4+1.9+2.8+0.5+2.3)÷15=23.466...

Since 23.466 > 21.733 then “The mean in period 2 is higher than the mean in period 1”.

7 0
2 years ago
Li Ping says a square with 3 inch sides has greater area than a parallelogram that is not a square but has sides that have the s
Kipish [7]

Answer:

Li Ping's statement makes sense.

Step-by-step explanation:

The area of a square with side lengths a inches is given by, A_1 = a^{2}.

Now, the area of a parallelogram with equal sides a inches, which is not a square is given by, A_2 = ah, where, h is the perpendicular distance between the opposite sides.

See the diagram attached.

Since a is the hypotenuse of as right triangle with height h, hence, a > h.

So, A_1 > A_2

Therefore, Li Ping's statement makes sense. (Answer)

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3 years ago
Henry has to wrap five presents
Dmitry_Shevchenko [17]
Henry has to wrap five presents for a birthday party and has a length of ribbon to make bows for the presents. He cuts the ribbon into eight equal lengths and uses five of the pieces. With the remaining length of ribbon he is able to make six bracelets to give away at the party
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Hi, im 13 years old, im responsible, and have a deep love for horses. Some tips on how to persuade my parents that i will be res
dimaraw [331]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A lampshade has a height of 12cm and upper and lower diameters of 10cm and 20cm A)what area of material is required to cover tha
netineya [11]

Answer:

(a)\ Area = 195\pi

(b)\ Volume = 700\pi

Step-by-step explanation:

Given

h = 12

d_1 = 10 --- lower diameter

d_2 = 20 --- upper diameter

Solving (a): The curved surface area

This is calculated as:

Area = \pi l(r_1 + r_2)

Where

r_1 = 0.5 * d_1 = 0.5 * 10 = 5 --- lower radius

r_2 = 0.5 * d_2 = 0.5 * 20 = 10 --- upper radius

And

l = \sqrt{h^2 + (r_1 - r_2)^2 ---- l represents the slant height of the frustrum

l = \sqrt{12^2 + (5 - 10)^2

l = \sqrt{12^2 + (-5)^2

l = \sqrt{144 + 25

l = \sqrt{169

l = 13

So, we have:

Area = \pi l(r_1 + r_2)

Area = \pi * 13(5 + 10)

Area = \pi * 13(15)

Area = 195\pi

Solving (b): The volume

This is calculated as:

Volume = \frac{1}{3}\pi * h * (r_1^2 + r_2^2 + (r_1 * r_2))

This gives:

Volume = \frac{1}{3}\pi * 12 * (5^2 + 10^2 + (5 * 10))

Volume = \frac{1}{3}\pi * 12 * (25 + 100 + (50))

Volume = \frac{1}{3}\pi * 12 * (175)

Volume = \pi *4 * 175

Volume = 700\pi

6 0
2 years ago
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