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3 years ago

What is the length of line segment EF?

Mathematics

2 answers:

luda_lava [24]3 years ago

8 0

The answer to this problem is...3.6

rosijanka [135]3 years ago

3 0

Answer:

EF = 3.6 is the answer.

Step-by-step explanation:

In the given picture coordinates of the endpoints of EF has been given and we have to calculate the length of the segment EF.

As we know when coordinates of two points are given and we have to calculate the distance between them we use the formula

Distance EF = √[(x - x')²+(y - y')²]

Here (x, y) and (x', y') are (-3, 1) and (-1, -2).

So distance EF = √(-3+1)²+(1+2)² =√(-2)²+(3)² = √(4 + 9) = √13

EF = 3.60

So the answer is 3.6

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Answer:

Part 1) $A=60\ ft^2$

Part 2) $A=80\ cm^2$

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Part 4) $A=144\ cm^2$

Part 5) $A=9\ m^2$

Part 6) $A=(49\pi -33)\ in^2$

Step-by-step explanation:

Part 1) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior rectangle

The area of rectangle is equal to

$A=bh$

where

b is the base of rectangle

h is the height of rectangle

$A=(12)(7)-(8)(3)$

$A=84-24$

$A=60\ ft^2$

Part 2) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior square

The area of square is equal to

$A=b^2$

where

b is the length side of the square

$A=(12)(8)-(4^2)$

$A=96-16$

$A=80\ cm^2$

Part 3) we know that

The area of the shaded region is equal to the area of four rectangles plus the area of one square

$A=4(4)(5)+(4^2)$

$A=80+16$

$A=96\ m^2$

Part 4) we know that

The shaded region is equal to the area of the complete square minus the area of the interior square

$A=(15^2)-(9^2)$

$A=225-81$

$A=144\ cm^2$

Part 5) we know that

The area of the shaded region is equal to the area of triangle minus the area of rectangle

The area of triangle is equal to

$A=\frac{1}{2}(b)(h)$

where

b is the base of triangle

h is the height of triangle

$A=\frac{1}{2}(6)(7)-(6)(2)$

$A=21-12$

$A=9\ m^2$

Part 6) we know that

The area of the shaded region is equal to the area of the circle minus the area of rectangle

The area of the circle is equal to

$A=\pi r^{2}$

where

r is the radius of the circle

$A=\pi (7^2)-(3)(11)$

$A=(49\pi -33)\ in^2$

7 0

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Step-by-step explanation:

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3 years ago