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2 years ago

What is the period of the graph of y=2 cos (pie/3 x ) +3 A.2 B.3/pie C.6 D.pie/3

Mathematics

1 answer:

Tatiana [17]2 years ago

6 0

Equate what is inside cosine with $2\pi$ , base period and solve for x,

$2\pi=\frac{\pi}{3}x$

$6\pi=\pi x$

$\boxed{x=6}$

Hope this helps :)

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Answer:

1/1

Step-by-step explanation:

1/6+5/6 simple adding with fractions its would be 1 foot

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3 years ago

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10. A taco stand sells tacos for $3.25 each. The stand’s expenses for the day are $210. Define your variables and write an inequ

makvit [3.9K]

X : number of tacos they sell per day. ...... profit = y = 3.25 × x - 210 ......inequality. y > 0. so. x > 210/3.25 = 840/13 = 64. ......so the taco stand must sell at least 65 tacos for making profit.

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3 years ago

Write an algebraic expression for the verbal description. the distance a car travels in t hours at a rate of 50 miles per hour

aleksklad [387]

The correct answer is
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6 0

2 years ago

I need help with this question

Novay_Z [31]

Answer:

$\frac{\sqrt{3} - 1}{2\sqrt{2}}$

$\frac{-(\sqrt{3} + 1)}{2\sqrt{2}}$

$- \frac{\sqrt{3} - 1}{\sqrt{3} + 1}$

Step-by-step explanation:

Given $\frac{11 \pi}{12} = \frac{3 \pi}{4} + \frac{\pi}{6}$

(A) $sin(\frac{11\pi}{12}) = sin (\frac{3 \pi}{4} + \frac{\pi}{6})$

We know that Sin(A + B) = SinA cosB + cosAsinB

Substituting in the above formula we get:

$sin (\frac{3\pi}{4} + \frac{\pi}{6}) = \frac{1}{\sqrt{2}} . \frac{\sqrt{3}}{2} + \frac{-1}{\sqrt{2}}. \frac{1}{2}$

$$ \implies \frac{1}{\sqrt{2}} (\frac{\sqrt{3} - 1}{2}) = \frac{\sqrt{3} - 1}{2\sqrt{2}}$

(B) Cos(A + B) = CosAcosB - SinASinB

$cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6}})$

$\implies \frac{-1}{\sqrt{2}}. \frac{\sqrt{3}}{2} - \frac{1}{\sqrt{2}} . \frac{1}{2}$

$\implies cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6})$

$$ = \frac{-(\sqrt{3} + 1)}{2\sqrt{2}}$

From the above obtained values this can be calculated and the value is $- \frac{\sqrt{3} - 1}{\sqrt{3} + 1}$ .

3 0

2 years ago

In the given figure, O is the centre of a circle, TN is a Tangent, AN = 12 cm and OE = 5 cm. Find the length of NE.

sp2606 [1]

Answer:

NE = 8 cm

Step-by-step explanation:

Radius OA = OE = 5 cm

In right triangle OAN, OA² + AN² = ON²

5² + 12² = ON²

ON² = 25 + 144 = 169

so ON = 13 cm

NE = ON - OE = 13 - 5 = 8 cm

3 0

2 years ago