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zimovet [89]
3 years ago
6

If h(x) = x2-5x + 7 find: ⅓ h(-8)

Mathematics
1 answer:
andrey2020 [161]3 years ago
6 0

Answer:

\displaystyle \frac{1}{3} h(-8) = 37

Step-by-step explanation:

Hi there!

h(x) = x^2-5x + 7

First, find h(-8) by replacing all of x with -8:

h(-8) = (-8)^2-5(-8) + 7\\h(-8) = 64+40 + 7\\h(-8) = 111

Now, find ⅓ h(-8) by multiplying the entire expression by ⅓:

\displaystyle \frac{1}{3} h(-8) = 111 * \frac{1}{3} \\\\\displaystyle \frac{1}{3} h(-8) = 37

I hope this helps!

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