Question

If h(x) = x2-5x + 7 find: ⅓ h(-8)

Answer 1

Answer:

$\displaystyle \frac{1}{3} h(-8) = 37$

Step-by-step explanation:

Hi there!

$h(x) = x^2-5x + 7$

First, find h(-8) by replacing all of $x$ with -8:

$h(-8) = (-8)^2-5(-8) + 7\\h(-8) = 64+40 + 7\\h(-8) = 111$

Now, find ⅓ h(-8) by multiplying the entire expression by ⅓:

$\displaystyle \frac{1}{3} h(-8) = 111 * \frac{1}{3} \\\\\displaystyle \frac{1}{3} h(-8) = 37$

I hope this helps!