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3 years ago

15x + 45 = 15 (3 + x) always never one solution how do I do it

Mathematics

2 answers:

const2013 [10]3 years ago

8 0

Answer:

Step-by-step explanation:

First, you need to try to get rid of the ().

To do this:

15 * 3 and 15 * x

This makes 45 and 15x after the = , so the formula is now:

15x + 45 = 45 + 15x

Now get the 15x to the left side. When a number switches sides, it becomes negative when positive and positive when negative. So in this case 15x will become -15x and the 45(on the left) becomes - 45

15x - 15x = 45 - 45

Answer: 0

Aleonysh [2.5K]3 years ago

8 0

15x + 45 = 45 + 15x
15x - 15x = 45 - 45
0x = 0 (*)
If we plug any real numbers of x to equation (*) we will always get 0 = 0
So the set of solutions of this question is all real numbers

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15x + 45 = 15 (3 + x) always never one solution how do I do it​

15x + 45 = 15 (3 + x) always never one solution how do I do it