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Dennis_Churaev [7]
3 years ago
13

Express the limit as a definite integral on the given interval.

Mathematics
1 answer:
san4es73 [151]3 years ago
3 0

9514 1404 393

Answer:

  \displaystyle\int^5_2 {(3x^3-7x)} \, dx

Step-by-step explanation:

The interval of interest becomes the limits of integration. ∆x becomes dx, and the xi are replaced by the variable of integration, x.

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Y=log(x-3)<br><br>what would be the base?
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By definition, if :

a^y = b

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<span>We highlight the following elements:

</span><span>a = Base of the logarithm;
b = logarithmand or antilogarithm
y = logarithm</span><span>

Therefore:

</span><span>Note that since the base was not specified, we know that it is equal to 10.
</span>
y = log_a b
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<span>
Answer:

</span>Base of the logarithm = 10
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