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Dennis_Churaev [7]
3 years ago
13

Express the limit as a definite integral on the given interval.

Mathematics
1 answer:
san4es73 [151]3 years ago
3 0

9514 1404 393

Answer:

  \displaystyle\int^5_2 {(3x^3-7x)} \, dx

Step-by-step explanation:

The interval of interest becomes the limits of integration. ∆x becomes dx, and the xi are replaced by the variable of integration, x.

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Twice the difference of a number and 9 equals 5.
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stiks02 [169]
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Find (f-g)(x) if f(x)=3x-5 and g(x)=x2-5x+4
solmaris [256]

Answer:

Step-by-step explanation:

Hello,

(f-g)(x)=f(x)-g(x)=3x-5-(x^2-5x+4)\\\\=3x-5-x^2+5x-4\\\\=-x^2+8x-9

Thanks

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