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3 years ago

Express the limit as a definite integral on the given interval.

Mathematics

1 answer:

san4es73 [151]3 years ago

3 0

9514 1404 393

Answer:

$\displaystyle\int^5_2 {(3x^3-7x)} \, dx$

Step-by-step explanation:

The interval of interest becomes the limits of integration. ∆x becomes dx, and the xi are replaced by the variable of integration, x.

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How do u describe the transformation needed from to get from figure A to B

andriy [413]

You have to be more specific to I can help

3 0

3 years ago

Jada received a gift of $180. In the first week, she spent a third of the gift money. She continues spending a

Sloan [31]

Answer:

180 minus 60 equals 120

Step-by-step explanation:

1/3 of 180 equals 60 so you would take 60 out of 180 to get 120 and 120 would be the amount that she spent the rest of the weeks

7 0

3 years ago

Some rectangles have an area of 36 cm². Let the variable W represent the width of these rectangles. Which expression represents

ZanzabumX [31]

Answer:

The perimeter of the rectangle is expressed as; $P = \frac{72 \ + \ 2W^2}{W}$

Step-by-step explanation:

Given;

area of the rectangle, A = 36 cm²

width of the rectangle, = W

Let L represent the length of the rectangle,

A = L x W

$L = \frac{A}{W} = \frac{36}{W}$

The perimeter of the rectangle is calculated as;

P = 2(L + W)

Substitute the value of L into the above equation;

$P = 2(L + W)\\\\P = 2 (\frac{36}{W} + W)\\\\P = 2 (\frac{36 + W^2}{W} )\\\\P = \frac{72 \ + \ 2W^2}{W}$

Thus, the perimeter of the rectangle is expressed as $P = \frac{72 \ + \ 2W^2}{W}$

8 0

3 years ago

-4/7 times what equals 32?

Savatey [412]

Answer: -4

Step-by-step explanation:

7 0

3 years ago

The general equation of the plane that contains the points (1, 0, 2), (−1, 1, −2), and the origin is of the form ax + by + cz =

ICE Princess25 [194]

Answer:

2x-z=0 is the equation of the plane.

Step-by-step explanation:

Given that the plane passes through the points (1,0,2) and (-1,1,-2)

and also origin.

Hence equation of the plane passing through three points we can use

Any plane passing through 3 given points is given as

$\left[\begin{array}{ccc}x-x_1&y-y_1&z-z_1\\x_2-x_1&y_2-y_1&z_2-z_1\\x_3-x_1&y_3-y_1&z_3-z_1\end{array}\right] =0$

Substitute the three points to get

$\left[\begin{array}{ccc}x-1&y&z-2\\-1-1&1&-2-2\\0-1&0&0-2\end{array}\right] \\=0\\(x-1)(-2) -y(4-4)+(z-2)(1) =0\\-2x+z=0\\2x-z-=0$

2x-z=0 is the equation of the plane.

4 0

4 years ago