Answer:
The length is 16 ft, and the width is 3 ft.
Step-by-step explanation:
Let L = length & let W = width.
The perimeter of a rectangle is
P = 2(L + W)
The area of a rectangle is
A = LW
We know the perimeter and the area, so we substitute those values int he equations above and we switch sides in both equations.
Perimeter: 2(L + W) = 38
Divide both sides by 2:
L + W = 19
Area: LW = 48
We have a system of two equations in two unknowns:
L + W = 19
LW = 48
Solve the first equation for L and substitute it into the second equation.
L = 19 - W
(19 - W)W = 48
19W - W^2 - 48 = 0
Multiply both sides by -1, and rearrange the order of the terms.
W^2 - 19W + 48 = 0
(W - 16)(W - 3) = 0
W - 16 = 0 or W - 3 = 0
W = 16 or W = 3
Use W = 3 to find L
L = 19 - W
L = 19 - 3
L = 16
Answer: The length is 16 ft, and the width is 3 ft.
There are a number of ways this can be done. One that is fairly simple is as follows.
Triangle ABC has base AC = 9 and height B to AC of 3 (found by counting squares). Thus its area is ∆ABC = (1/2)·9·3 = 13.5 square units.
Triangle ACF has base AC = 9 and height F to AC of 3, so will have the same area as triangle ABC, 13.5 square units.
Trapezoid CDEF has base CD of 6, base EF of 4 and height EF to CD of 6 (found by counting squares). Thus its area is CDEF = (1/2)(6 + 4)(6) = 30.
The total area of the entire figure is then
... ∆ABC + ∆ACF + CDEF = 13.5 + 13.5 + 30 = 57 square units.
10in = 0.833333ft^2 that is the total amount for one side. For a cube that has 6 sides, you multiply 0.833333 by 6.
You need <span>4.999998ft^2 of paper</span>
Answer:
Hey
Step-by-step explanation:
Sorry I need the points asap
