A cannon is on the edge of a cliff 5.2 x 102 m above the ground. A cannon ball leaves the cannon at 1.5 x 102 m/s. If the cannon
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Answer:
Explanation:
If the passage of the waves is one crest every 2.5 seconds, then that is the frequency of the wave, f.
The distance between the 2 crests (or troughs) is the wavelength, λ.
We want the velocity of this wave. The equation that relates these 3 things is
and filling in:
so
v = 2.5(2.0) and
v = 5.0 m/s
