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3 years ago

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A cannon is on the edge of a cliff 5.2 x 102 m above the ground. A cannon ball leaves the cannon at 1.5 x 102 m/s. If the cannon

aimed at an angle of of 60. degrees above the horizontal (i.e. aimed upward) what is the:
a) Time of flight?

b) The range of the cannon ball?

1 answer:

marusya05 [52]3 years ago

4 0

Answer: i dont know yet

Explanation:

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Use F = 1/T as your basis:

skelet666 [1.2K]

Time Period=T=2.5×10^{-3}s

Now

Frequency:-

$\\ \rm\rightarrowtail \nu=\dfrac{1}{T}$

$\\ \rm\rightarrowtail \nu=\dfrac{1}{2.5\times 10^{-3}}$

$\\ \rm\rightarrowtail \nu=0.4\times 10^{3}$

$\\ \rm\rightarrowtail \nu=400Hz$

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