As both the skater pushed each other with a force, skater 1 will acquire greater velocity than skater 2 with heavier mass.
Answer: Option C
<u>Explanation:</u>
Here we can understand the scenario with the example of a particle collision. When two particles of different masses, one being lighter and the other being heavier, there will be a movement and change in velocities.
Now, when these two particle collide with each other, there will be an equal and opposite thrust or reaction on both the particles. The particle with heavier mass will not be able to acquire more velocity because of its weight whereas the lighter particle will be pushed far away, being less in mass.
We can also say that the heavier particle will exert more force as compared to the lighter one and hence, can easily push it far away. this is all because the force is directly proportional to the mass of the object.
Hence, just like the particle, when two skater try to push each other with a significant amount of force, skater 2 will win to exert more force and therefore, skater 1 will acquire greater velocity as compared to skater 2.
<span>We know that pressure is the force applied into a surface, in our case the wall of the room, so then first we will calculate the surface of this wall:
S = 2.2 * 3.2 = 7.04 m2
Then we also know the atmospheric pressure in normal conditions is 1 atm. That is the same 1 atm = 101325 Pascals or 101325 N/m2
Now we need to use the formula : P = F/S where P is pressure, F is force and S is surface to calculate the force:
F = P * S = 101325 * 7.04 = 713,328 Newtons
Conclusion: the force acts on the wall due the air inside the room is 713,328 N</span>
Answer:
Application of Newton's first law of motion
A body in motion will continue in motion in a straight line unless acted upon by an outside force.
Explanation:
Answer:
c)
Explanation:
As we know that resultant force is the net force that is acting on the system
As per Newton's II law we know that net force is product of mass and acceleration
so we will have
here we know
m = 80 kg
for circular motion acceleration is given as
now we have