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Anastaziya [24]
3 years ago
15

How much power is required to carry a 35 N package a vertical distance of 18 m if the work on the package is accomplished in 30

s?
Physics
1 answer:
mars1129 [50]3 years ago
3 0

Answer:

P = 21 watts

Explanation:

Given that,

Weight of a package, F = 35 N

Distance, d = 18 m

Time, t = 30 s

We need to find the power required to carry the package. Power is equal to the work done divided by time. So,

P=\dfrac{W}{t}\\\\P=\dfrac{Fd}{t}\\\\P=\dfrac{35\times 18}{30}\\\\P=21\ W

So, the required power is 21 watts.

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3 years ago
What’s the difference between applied and pure research
Ket [755]

Answer:

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8 0
3 years ago
For installation with a 25-kVA, 3-phase transformer, a 440-volt primary, and a 120-volt secondary. Calculate the maximum overcur
andre [41]

Answer:

41.053 A

Explanation:

given,

three phase kVA = 25-kVA

voltage = 440 Volt

current = ?

To determine three phase kVA when volts and amperes are know

   three phase kVA = 1.73 x V x I

    I = \dfrac{three\ phase\ kVA}{1.73 \times V}

    I = \dfrac{25000}{1.73 \times 440}

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4 0
3 years ago
A person who weighs 509,45 N empties her lungs as much as
Masja [62]

Answer:

The weight of the girl = 1045.86 kg/m³

Explanation:

Density: This can be defined as the ratio of the mass of a body to the volume of that body. The S.I unit of density is kg/m³.

From Archimedes principle,

R.d = Density of the person/Density of water = Weight of the person in air/Upthrust.

⇒ D₁/D₂ = W/U............................... Equation 1.

Where D₁ = Density of the person, D₂ = Density of water, W = Weight of the person in air, U = Upthrust in water.

Making D₁ the subject of the equation,

D₁ = D₂(W/U)................................... Equation 2

<em>Given: D₂ = 1000 kg/m³ , W = 509.45 N, U = lost in weight = weight in air - weight in water = 509.45 - 22.34 = 487.11 N</em>

<em>Substituting these values into equation 2</em>

D₁ = 1000(509.45/487.11)

D₁ = 1045.86 kg/m³

Thus the weight of the girl = 1045.86 kg/m³

<em></em>

7 0
3 years ago
When do two different position-time graphs have<br> matching velocity-time graphs?
Ivan

Answer:

when they have the same slope

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