Question

How much power is required to carry a 35 N package a vertical distance of 18 m if the work on the package is accomplished in 30 s?

Answer 1

Answer:

P = 21 watts

Explanation:

Given that,

Weight of a package, F = 35 N

Distance, d = 18 m

Time, t = 30 s

We need to find the power required to carry the package. Power is equal to the work done divided by time. So,

$P=\dfrac{W}{t}\\\\P=\dfrac{Fd}{t}\\\\P=\dfrac{35\times 18}{30}\\\\P=21\ W$

So, the required power is 21 watts.