The vertex is (8,7)
the minimum value is 7
the vertex form is y=(x-8)^2 +7
the minimum value of y=7
i hope this helps!
Answer:
D) -4, 0
Step-by-step explanation:
find common difference.
the common difference appears to be +4 as you must add 4 to -12 to get to -8
now we find the missing terms.
the previous term of the first missing term is -8
if the common difference is +4 then the next term would be -8 + 4 = -4
the term after that would be -4 + 4 = 0
the two missing terms are -4 and 0
Answer:
The two step equation that we can use to find michael's age is x = (f-2)/4 where f = 30. So Michael is 7 years old.
Step-by-step explanation:
In order to solve this problem we will attribute variables to the ages of Michael and his father. For his father age we will attribute a variable called "f" and for Michael's age we will attribute a variable called "x". The first information that the problem gives us is that Michael's dad is 30 years of age, so we have:
f = 30
Then the problem states that the age of the father is 2 years "more" than four "times" Michaels age. The "more" implies a sum and the "times" implies a product, so we have:
f = 2 + 4*x
We can now find Michael's age, for that we need to isolate the "x" variable. We have:
f - 2 = 4*x
4*x = f - 2
x = (f-2)/4
x = (30 - 2)/4 = 7 years
The two step equation that we can use to find michael's age is x = (f-2)/4 where f = 30. So Michael is 7 years old.
So first +9 to both sides to isolate the variable. Then you’ll be left with 10 is greater than or equal to x. So if you switch the terms around it’ll be x is less than or equal to 10. Values that are less than or equal to 10 are like 10,9,8,7,etc.
Take the expression in chunks:
>>

>>



>>
Note that
. So

where the cyclic sum notation means

In other words, we take the sum over all possible cycles of the sequence of arguments to the summand. The second square-bracketed chunk reduces to

So to recap, we've reduced the starting expression to

>>

Finally, we have

Then distributing
and rewriting to decode the message, we have
