Here is the complete question.
Glycerol (C3H8O3), also called glycerine, is widely used in the food and pharmaceutical industries. Glycerol is polar and dissolves readily in water and polar organic solvents like ethanol. Calculate the mole fraction of the solvent in a solution that contains 1.61 g glycerol dissolved in 22.60 mL ethanol (CH3CH2OH; density = 0.7893 g/mol). Round to four significant digits
Answer:
0.9567 mol
Explanation:
Given that:
mass of glycerol = 1.61 g
molar mass of glycerol = 92.1 g/mol
no of mole = 
∴ number of moles of glycerol (
) = 
= 0.0175 mol
Volume of ethanol = 22.60 mL
Density of ethanol = 0.7893 g/mL
Since Density = 
∴ mass of ethanol = density of ethanol × volume of ethanol
mass of ethanol = 0.7893 g/mL × 22.60 mL
mass of ethanol = 17.838 g
Number of moles of ethanol 
= 
= 0.387 mole
∴ the mole fraction of the solvent can be determined as:
= 0.95673671199
≅ 0.9567 mol
∴ The mole fraction of the solvent in a solution that contains 1.61 g glycerol dissolved in 22.60 mL ethanol is = 0.9567 mol
Answer:
dentify the common substance that has the highest density. A) glass. B) ethanol. C) aluminum
Explanation:
Answer:
2.33 mL
Explanation:
Given data
- Initial pressure (P₁): 1 atm (Standard pressure)
- Initial volume (V₁): 80.0 mL
- Initial temperature (T₁): 273.15 K (Standard temperature)
- Final pressure (P₂): 92.0 atm
- Final temperature (T₂): 460°C + 273.15 = 733 K
We can find the new volume using the combined gas law.
Answer:
17.76g
Explanation:
We need to write a balanced chemical equation for the reaction:
2Al(OH)3 + 3Ca(NO3)2 ——> 3Ca(OH)2 + 2Al(NO3)3
In the reaction above, it can be seen that 2 moles of aluminum hydroxide yielded 3 moles of calcium hydroxide. This is the theoretical viewpoint.
Now we need to know what actually happened. We need to calculate the actual number of moles of aluminum hydroxide reacted l. We can get this by dividing the mass by the molar mass.
The molar mass of aluminum hydroxide is 27+ 3( 16+1)
= 27 + 51 = 78g/mol
The number of moles is thus: 12.55/78 = 0.16 moles
Now if 2 moles of aluminum hydroxide gave 3 moles of calcium hydroxide, 0.16moles will give : (0.16*3)/2 = 0.24moles
Now we can calculate the mass of calcium hydroxide formed. The mass of calcium hydroxide formed is the number of moles multiplied by the molar mass.
The molar mass of calcium hydroxide is; 40 + 2(17) = 74g/mol
The mass is thus =74 * 0.24 = 17.76g
Answer:
WHY: You can abbreviate an element's electron configuration using the noble gas notation method because when you get down to the lower elements, specifically the d's and the f's, the electron configuration will be very long. The noble gas notation method is a faster answer while also being correct.
HOW: We can abbreviate an element's electron configuration by finding the last noble gas a specific element passed, for example calcium would have just passed Argon. Once you have the "address" of the previous noble gas, then you add on the difference between the element chosen and the noble gas, for example calcium would be [Ar] 4s^2.
Explanation:
