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Sonbull [250]
3 years ago
7

Prove the conservation of linear momentum​

Physics
1 answer:
Irina18 [472]3 years ago
8 0

Answer:

force experienced by A and B are equal and opposite, that is total momentum before collision is equal to total momentum after collision if no external forces act on them which proves the principle of conservation of linear momentum.

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A sandbag motionless in outer space is hit by a three-times-as massive sandbag moving at 12 m/s. They stick together. This is an
vekshin1

Answer:

This is an example of inelastic collision and it loses zero(0) % of initial kinetic energy

Explanation:

Let the mass of the motionless sandbag = m₁

Let the mass of the moving sandbag = m₂ = 3m₁

initial velocity of the motionless sandbag, u₁ = 0

initial velocity of the moving sandbag, u₂ = 12 m/s

Let their final velocity, = v

Collision between two particles can either be elastic or inelastic.

Since they stick together after the impact, then the collision is inelastic

Apply the principle of conservation of linear momentum;

Initial kinetic energy = final kinetic energy

¹/₂m₁u₁² + ¹/₂m₂u₂² = ¹/₂v²(m₁ + m₂)

¹/₂m₁(0)² + ¹/₂(3m₁)(12)² = ¹/₂v²(m₁+3m₁)

216m₁ = 2m₁ v²

v² = 108

v = √108

v = 10.392 m/s

Change in kinetic energy = Final kinetic energy - initial kinetic energy

Initial Kinetic energy, KE₁ = ¹/₂m₁u₁² + ¹/₂m₂u₂²

                                   KE₁ = ¹/₂m₁(0)² + ¹/₂(3m₁)(12)²

                                   KE₁ = 216m₁ J

Final kinetic energy, KE₂ = ¹/₂v²(m₁ + m₂)

                                  KE₂ = ¹/₂(108)(m₁ + 3m₁)

                                  KE₂ = 216m₁ J

ΔKE = KE₂ - KE₁ =  216m₁ J -  216m₁ J = 0%

Therefore, this is an example of inelastic collision and it loses zero(0) % of initial kinetic energy

4 0
3 years ago
The drawing shows a hydraulic chamber with a spring (spring constant = 1600 N/m) attached to the input piston and a rock of mass
Triss [41]

Answer:

\Delta x=245\ mm

Explanation:

Given:

  • spring constant of the spring attached to the input piston, k=1600\ N.m^{-1}
  • mass subjected to the output plunger, m=40\ kg

<u>Now, the force due to the mass:</u>

F=m.g

F=40\times 9.8

F=392\ N

<u>Compression in Spring:</u>

\Delta x=\frac{F}{k}

\Delta x=\frac{392}{1600}

\Delta x=0.245\ m

or

\Delta x=245\ mm

8 0
4 years ago
Overlearning is
scoundrel [369]
A method for improving your memory…
7 0
3 years ago
What happens to a light if the switch is turned off in the circuit?
lukranit [14]

In a parallel circuit nothing happens. All the other lights stay on but if it was a series circuit ALL the lights would turn off at one time.

If there is an ABCD question I can answer that but I wasn't sure so I just said this

Hope it is helpful :)

6 0
3 years ago
Suppose I produce radio waves with an antenna that have a peak electric field amplitude E and peak magnetic field amplitude B. I
denis23 [38]

Answer:

Correct answer is 2B

Explanation:

The electric field magnitude and magnetic field magnitude in an electromagnetic waves are related as under

E=cB

where 'c' is velocity of light in the medium of transmission

According to the given question if we double the electric field we have

2E=cB'\\\\2cB=cB'\\\\B'=2B

Thus the magnetic field also doubles

3 0
3 years ago
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