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Elis [28]
3 years ago
8

Select the correct answer

Physics
2 answers:
Monica [59]3 years ago
8 0

Explanation:

Constant speed => Zero acceleration

Since Fnet = ma, when a = 0, Fnet = 0.

The best answer here is:

"The net force acing on the car from all directions is zero."

Rasek [7]3 years ago
5 0

Answer:

I would say the net force acting on the car is in the opposite direction of the car's motion  is correct

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Someone fires a 0.04 kg bullet at a block of wood that has a mass of 0.5 kg. (The block of wood is sitting on a frictionless sur
lidiya [134]

Answer:

22.22m/s

Explanation:

The momentum before a collision = momentum after collision so...

work out the momentum of the first object (the bullet)

its p = mv

0.04 kg × 300 m/s  = 0.54 kg × v

rearrange this to find v which is 0.04 x 300 = 12

so 12 = 0.54 x v

    12/0.5 = v

    v = 22.22m/s

hope this helps!

7 0
3 years ago
A strong but negative correlation indicates that the two variables studied are not related.
Doss [256]
The answer is false.
3 0
3 years ago
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What are the effects of noise?​
slega [8]

Answer:

Noise making has led to loss on hearing.

Explanation:

Supposing you like engaging in parties because of the noise of the sound system it can cause loss on hearing if continued for long

6 0
4 years ago
7 I'LL GIVE BRAINLIST!!!
goldenfox [79]

Answer:

Below

Explanation:

1. Everest

2. Godwin Austen

3. Kangchenjunga

4. Lhotse

5. Makalu

6. Cho Oyu

7. Dhaulagiri

8. Manaslu

9. Nanga Parbat

10. Annapurna

Sorry I don't know anything about their types :(

I hope this helps you :)

4 0
3 years ago
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For copper, ρ = 8.93 g/cm3 and M = 63.5 g/mol. Assuming one free electron per copper atom, what is the drift velocity of electro
viktelen [127]

Answer:

V_d = 1.75 × 10⁻⁴ m/s

Explanation:

Given:

Density of copper, ρ = 8.93 g/cm³

mass, M = 63.5 g/mol

Radius of wire = 0.625 mm

Current, I = 3A

Area of the wire, A = \frac{\pi d^2}{4} = A = \frac{\pi 0.625^2}{4}

Now,

The current density, J is given as

J=\frac{I}{A}=\frac{3}{ \frac{\pi 0.625^2}{4}}= 2444619.925 A/mm²

now, the electron density, n = \frac{\rho}{M}N_A

where,

N_A=Avogadro's Number

n = \frac{8.93}{63.5}(6.2\times 10^{23})=8.719\times 10^{28}\ electrons/m^3

Now,

the drift velocity, V_d

V_d=\frac{J}{ne}

where,

e = charge on electron = 1.6 × 10⁻¹⁹ C

thus,

V_d=\frac{2444619.925}{8.719\times 10^{28}\times (1.6\times 10^{-19})e} = 1.75 × 10⁻⁴ m/s

4 0
3 years ago
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