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scoundrel [369]
3 years ago
14

A car is moving from rest and the velocity increases to 30 m/s in 4 seconds. Calculate its acceleration.

Physics
1 answer:
vaieri [72.5K]3 years ago
8 0

Answer:

7.5 m/s²

Explanation:

Given:

v₀ = 0 m/s

v = 30 m/s

t = 4 s

Find: a

v = at + v₀

(30 m/s) = a (4 s) + (0 m/s)

a = 7.5 m/s²

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The image represents a sound wave as it goes through several changes. Describe how the waves changes. where does it get louder?
Ksju [112]

Answer:

At point A. it gets kinda loud then at point B. it gets very loud than at point C. it gets quieter than at point D. it gets more silent.

Explanation:

Because you can tell when the waves get large it gets louder and then when the waves get more far apart then it get more quiet. Hope this helped!

4 0
3 years ago
a steam engine work on its vicinity 285 k heat is released with the help of 225 c energy absorbed to the system what is the effi
zvonat [6]

The efficiency of steam engine is  26.66 %.

<h3>What is Efficiency?</h3>

The efficiency is defined as the work done by the engine divided by the heat supplied.

Work done is the difference between the heat supplied and heat rejected.

So, efficiency η = (Qs -Qr) / Qs

Given is the heat supplied Qs = 225 Joules and heat rejected Qr =285 . then the work done is

W = 225 -225 = - 60 Joules

Efficiency η  = 60/225 x 100%

η = 26.66 %

Thus, the efficiency of the steam engine is  26.66 %.

Learn more about efficiency.

brainly.com/question/13828557

#SPJ2

8 0
2 years ago
Read 2 more answers
The 68-kg crate is stationary when the force P is applied. Determine the resulting acceleration of the crate if (a) P = 0, (b) P
bogdanovich [222]

Explanation:

Mass of the crate, m = 68 kg

We need to find the resulting acceleration if :

(a) Force, P = 0

P = m a

⇒ a = 0

(b) P = 181 N

a=\dfrac{P}{m}

a=\dfrac{181\ N}{68\ kg}

a=2.67\ m/s^2

(c) P = 352 N

a=\dfrac{P}{m}

a=\dfrac{352\ N}{68\ kg}

a=5.17\ m/s^2

Hence, this is the required solution.

5 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs.
zhannawk [14.2K]
This is the match:

1) stored energy related to positions of atoms within molecules ↔ chemical energy

Explanation: the chemical energy is the energy stored in the bonds that binds the atoms that form the molecules.

2) energy released when a nucleus splits or combines ↔ nuclear energy

Explanation: there is a huge energy inside an atom which may be released when nuclei suffer fusion (combination of nuclei) or fission (split of nuclei). The fusion of atoms is what happens in stars and it is the source of their energy. Fision of atoms is the nuclear energy used in the nuclear plants to produce electricity.

3) energy related to an object's movement ↔ motion energy

Explanation:

The motion energy is the kinetic energy, KE. KE = (1/2) m* v^2

4) energy related to heigth ↔ gravitaional potential energy

The higher an object is the higher its gravitational potential energy, PE.

PE = m*g*h.

5) energy related by vibration of a string ↔ sound energy

Explanation:

Sure you have seen that: when the string of a guitar vibrate the sound is produced.

6) energy of motion of particles in a substance ↔ thermal energy

The thermal energy is the product of the motions (vibration, translation and collisions) of the molecules that form the substance. The higher the motion the the higher the thermal energy measured as temperature.
4 0
4 years ago
Read 2 more answers
It's nighttime, and you've dropped your goggles into a 3.1-mm-deep swimming pool. If you hold a laser pointer 1.2 mm above the e
arlik [135]

Answer:

the googles are 4.33mm from the edge

Explanation:

In this question, we are asked to calculate the distance of a set of googles from the edge of a pool.

We proceed as follows;

depth of pool , d = 3.1mm

Now, let i be the angle of incidence

i = arctan(1.8/1.2)

i = 56.31 degree

Using snell's law ,

n1 * sin(i) = n2 * sin(r)

1 * sin(56.3) = 1.33 * sin(r)

r = 38.72 degrees

Now,

distance of googles = 1.8+ d*tan(r)

distance of googles = 1.8+ 3.1 * tan(38.72)

distance of googles = 4.3 mm

5 0
3 years ago
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