Answer:
<em>C. Zero </em><em>acceleration</em><em>.</em><em>.</em><em>.</em><em>.</em>
Answer:
e. Reduced conflict.
Explanation:
Outsourcing is a tool that allows you to hire a provider outside the company for the execution of secondary activities, such as cleaning or mail, or covering other areas of the company, such as financial or accounting systems or the human resources area
- Advantages of Outsourcing
- Cost reduction
- Focus on the main activity
- Transformation of fixed costs into variables
- Reduce risk
- Improve quality
- Productivity increase
- Improve innovation processes
- Greater flexibility
- Access to the latest technologies
- Increase in competitiveness
Answer:
When you travel at a slower speed it takes you longer time to travel same distance. This makes the slower speed have more weight in the average speed.
The average speed is based on total time taken. So now you do some work.
Assume you traveled x kilometer up hill and then the same x kilometer down hill. Find out the total time taken. Divide the total distance traveled by total time taken. You will find it will be 24. So even if you traveled some distance on the flat ground at 24 kph.
The average will always be 24 kph.
First, calculate how long the ball is in midair. This will depend only on the vertical displacement; once the ball hits the ground, projectile motion is over. Since the ball is thrown horizontally, it originally has no vertical speed.
t = time vi = initial vertical speed = 0m/s g = gravity = -9.8m/s^2 y = vertical displacement = -45m
y = .5gt^2 [Basically, in this equation we see how long it takes the ball to fall 45m] -45m = .5 (-9.8m/s^2) * t^2 t = 3.03 s
Now we know that the ball is midair for 3.03s. Since horizontal speed is constant we can simply use:
x = horizontal displacement v = horizontal speed = 25m/s t = time = 3.03s
x = v*t x = 25m/s * 3.03s = 75.76 m Thus, the ball goes about 75 or 76 m from the base of the cliff.
Answer:
16 seconds
Explanation:
Solution.
We are to determine the time required to heat a mass of water with a temperature change of 2 K, with an electric resistance of 24 V and current intensity of 1A.
Assumptions:
Steady state condition, since the temperature change is small.
All of the electric energy is converted into heat by the resistance.
Analysis.
When the steady state conditions are reached, the heat loss of the resistance will be equal to the heat generation rate of the electric resistance; meaning,
Q’=Q/ Δt =E’,generated=V*i
Where
Q is the heat transferred to the water, evident as latent heat. Then,
Q=m,w*Cp,w*ΔT/Δt=V*i
Then,
Δt= m,w*Cp,w*ΔT/(V*i)
Replacing values
Δt=(46 g)*(4.18 J/g K)*(2 K)/(24 J/A s *1A)
Δt=16 s
Discussion.
For this problem, we could also consider a transient state condition, that includes the temperature profile change within the resistance (given that we have the mass and specific heat information). However, we would require more information about the geometry in order to evaluate the heat transfer coefficients to the water. Also, the heating time of 16 seconds is quite reasonable given the mass of water and the electric resistance of 24 V.