Question

Help for 15 points . ill up it

Answer 1

Step-by-step explanation:

Let $P_1(-1, -8)\:\text{and}\:P_2(-4, -9)$

The slope of the line through these two points is

$m = \dfrac{y_2 - y_1}{x_2 - x_1} = \dfrac{(-9 + 8)}{(-4 + 1)} = \dfrac{1}{3}$

So the slope-intercept form of the line passing through the two points is

$y = mx + b = \frac{1}{3}x + b$

To find b, we use either point into our equation. Let's use (-1, -8):

$-8 = \frac{1}{3}(-1) + b \Rightarrow b = -\dfrac{23}{3}$

Therefore, the slope-intercept form of the equation for the line is

$y = \dfrac{1}{3}x - \dfrac{23}{3}$

The standard form of the equation can be written as

$x + 3y + 23 = 0$