Answer:
12
Step-by-step explanation:
We consider the x- and y-coordinates separately. Let the coordinates of G be (x, y). Now considering the x-coordinates:
FG/FH = (x - (-3)) / (-3 - (-3)) = 2/3
x + 3 = (2/3)(6)
x = 1
For the y-coordinates:
FG/FH = (y - 2) / (7 - 2) = 2/3
y - 2 = (2/3)(5)
y = 16/3
Therefore the coordinates of G are (1, 16/3).
Answer:
The equation of line with given points and perpendicular to y-axis is
y = - 7
Step-by-step explanation:
Given as :
The given points as ( - 10 , - 7)
The equation of line is Y = mX + c
So The line will satisfy given points
Or, - 7 = m ( -10 ) + c
Now This line is perpendicular to y- axis
∴ The slop of line perpendicular to y axis is 0
So, - 7= 0 + c
or, c = - 7
∴ Equation of line is y = 0 + c
Or, y = - 7
Hence The equation of line with given points and perpendicular to y-axis is y = - 7 Answer
Answer:
Total number of possible combinations are 6
Length width
23 dm 2m
21 dm 4 dm
19 dm 6 dm
17 dm 8 dm
15 dm 10 dm
13 dm 12 dm
Step-by-step explanation:
We are given that
Perimeter of rectangular garden=50 dm
Width is even number.
Length is always longer than or equal to width.
Let length of rectangular garden=x
Width of rectangular garden=y
We have to find the possible number of combinations .
Perimeter of rectangular garden=



If y=2 dm
x=25-2=23 dm
If y=4 dm
x=25-4=21 dm
If y=6 dm
x=25-6=19 dm
If y=8 dm
x=25-8=17 dm
If y=10 dm
x=25-10=15 dm
If y=12 dm
x=25-12=13 dm
If y=14 dm
x=25-14=11 dm
x<y
It is not possible
Then, possible combinations are 6
Length width
23 dm 2m
21 dm 4 dm
19 dm 6 dm
17 dm 8 dm
15 dm 10 dm
13 dm 12 dm