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LiRa [457]
3 years ago
11

The temperature is -2 if the temperature rises by 15 what is the new temperature​

Mathematics
2 answers:
Ksenya-84 [330]3 years ago
8 0
13 degrees Celsius (or whatever counter your country uses)
givi [52]3 years ago
7 0
The temperature would be 13.
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Please can someone help?
Alina [70]

Step-by-step explanation:

R = 6.5cm and r = 2.3 cm

area of the shaded region = area of the outer circle - area of the inner circle

= πR²-πr²

=π(R²-r²)

=π{(6.5)²-(2.3)²}

=π (42.25-5.29)

= 3.14× 36.96

= 115.866

= 116 cm²

6 0
3 years ago
Please help meeeeee ://
a_sh-v [17]
A). They are supplementary angles meaning they add up to 180
So
B) (12x+8)+(3x+7)=180
12x+8+3x+7=180
15x+15=180
-15 -15
15x=165
15/15x=165/15
x=11

Angle 1 is
12x+8
12(11)+8
132+8
140
Therefore measure of angle 1 is 140°

Angle 2
3x+7
3(11)+7
33+7
40
Measure of angle 2 is 40°

8 0
3 years ago
Help and show work that will make my day ❤️
kolezko [41]
H equals 30 because 3 times 6 is 18 so 5 times 6 is 30
7 0
3 years ago
6m-1= What is the answer
NeTakaya
<span>6m + 1 = 23 Reorder the terms: 1 + 6m = 23 Solving 1 + 6m = 23 Solving for variable 'm'. Move all terms containing m to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 6m = 23 + -1 Combine like terms: 1 + -1 = 0 0 + 6m = 23 + -1 6m = 23 + -1 Combine like terms: 23 + -1 = 22 6m = 22 Divide each side by '6'. m = 3.666666667 Simplifying m = 3.666666667 i think</span>
7 0
3 years ago
A population of 30 deer are introduced into a wildlife sanctuary. It is estimated that the sanctuary can sustain 600 deer. The p
Ksju [112]

Complete question :

A population of 30 deer are introduced into a wildlife sanctuary. It is estimated that the sanctuary can sustain 600 deer. The population would grow by 30 percent per year

how many after one year

how many after two years

Answer:

39 deers

51 deers

Step-by-step explanation:

The question can be expressed using the compounding rate formula:

A = P(1+r)^t

A = final population ; P = initial population ; rate, r = 30% = 0.3 ; t = time

After 1 year, t = 1

A = 30(1 + 0.3)^1

A = 30(1.3)^1

A = 39 deers

B.)

After 1 year, t = 2

A = 30(1 + 0.3)^2

A = 30(1.3)^2

A = 50.7

A = 51 deers approximately

4 0
3 years ago
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