Part 2 5. -0.3 ÷ (-0.27) 6. -5.5 ÷ 0.021 7. -412 ÷ -334 8. 7.75 ÷ ( -123)
1 answer:
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Answer:
121
Step-by-step explanation:
Given data as per the question
Standard deviation = = 840
Margin of error = E = 150
Confidence level = c = 95%
For 95% confidence, z = 1.96
based on the above information, the minimum number of clients surveyed by the travel agent is
= 120.47
= 121
hence, the 121 number of clients to be surveyed
Therefore we applied the above formula to determine the minimum number of clients
Answer:
a. z=3.09. Yes, it can be concluded that the population mean is greater than 50.
b. z=1.24. No, it can not be concluded that the population mean is greater than 50.
c. z=2.22. Yes, it can be concluded that the population mean is greater than 50.
Step-by-step explanation:
We have a hypothesis test for the mean, with the hypothesis:
The sample size is n=55 and the population standard deviation is 6.
The significance level is 0.05.
We can calculate the standard error as:
For a significance level of 0.05, the critical value for z is zc=1.644. If the test statistic is bigger than 1.644, the null hypothesis is rejected.
a. If the sample mean is M=52.5, the test statistic is:
The null hypothesis is rejected, as z>zc and falls in the rejection region.
b. If the sample mean is M=51, the test statistic is:
The null hypothesis failed to be rejected, as z<zc and falls in the acceptance region.
c. If the sample mean is M=51.8, the test statistic is:
The null hypothesis is rejected, as z>zc and falls in the rejection region.