Answer:
I think the answer is 3 option
The ratio for this problem is 1:5.
If you are drawing 14 pentagons, you would do 14 x 5.
14 (pentagons) x 5 (line segments) = 70 line segments in total.
The answer is C) 70
Answer: a = -2/3
Step-by-step explanation:
Let's start by multiplying both sides by
to simplify:
![$4^{1/3} = x^a \times x$](https://tex.z-dn.net/?f=%244%5E%7B1%2F3%7D%20%3D%20x%5Ea%20%5Ctimes%20x%24)
![$4^{1/3} = \underbrace{x \times x \times x \times \cdots \times x}_{a\ \textrm{times}} \times \,x$](https://tex.z-dn.net/?f=%244%5E%7B1%2F3%7D%20%3D%20%5Cunderbrace%7Bx%20%5Ctimes%20x%20%5Ctimes%20x%20%5Ctimes%20%5Ccdots%20%5Ctimes%20x%7D_%7Ba%5C%20%5Ctextrm%7Btimes%7D%7D%20%5Ctimes%20%5C%2Cx%24)
![$4^{1/3} = \underbrace{x \times x \times x \times \cdots \times x \times x}_{a+1\ \textrm{times}}$](https://tex.z-dn.net/?f=%244%5E%7B1%2F3%7D%20%3D%20%5Cunderbrace%7Bx%20%5Ctimes%20x%20%5Ctimes%20x%20%5Ctimes%20%5Ccdots%20%5Ctimes%20x%20%5Ctimes%20x%7D_%7Ba%2B1%5C%20%5Ctextrm%7Btimes%7D%7D%24)
![4^{1/3} = x^{a+1}](https://tex.z-dn.net/?f=4%5E%7B1%2F3%7D%20%3D%20x%5E%7Ba%2B1%7D)
Looking only at the exponents, it seems like
, so
.
First, we need to work out the total number of students who were being surveyed.
We know that half of the students has two pets. The rest of the students make up the other half. So, we have 3 students + 2 students + 8 students = 13 students that make half of the sample population
That means total number of students being surveyed is 13+13=26 students
Then we work out the probability
P(One pet) = 8/26 = 4/13
P(Two pets) = 1/2
P(Three pets) = 3/26
P( Four pets) = 2/26 = 1/13
The probability distribution is shown in the table below. Let
![x](https://tex.z-dn.net/?f=x)
be the number of pets and
![P(X=x)](https://tex.z-dn.net/?f=P%28X%3Dx%29)
is the probability of owning the number of pets
Answer:
1,262.5
according to the calculator lol