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3 years ago

15

Explain how in glycolysis that the splitting of one glucose molecule results in 4 ATP but there Is only a net gain of 2 ATP.

1 answer:

gayaneshka [121]3 years ago

8 0

Answer:

Explanation:

During glycolisys in cytoplasm, first step involves adding two phosphates to glucose molecule. This step requires the use of two ATP molecules. The next step is splitting 6 carbons glucose into two 3 carbons pyruvates. This step produces 4 ATPs and 2 NADHs. However, since we used up two ATPs during the initial phosphorylation, the net gain is only 2 ATPs

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g Indium has two naturally occurring isotopes: 113In with an atomic weight of 112.904 amu, and 115In with an atomic weight of 11

aleksandrvk [35]

Answer:

Fraction-of-occurrences of 115In isotope $= 0.957$

Explanation:

As we know weight of 113 In isotope is equal to the sum of product of fraction-of-occurrences of two constituents isotopes and their atomic weight

$^{115}In_w = f_{113}*A_{113} + f_{115}*A_{115}$ ------(1)

As we know sum of fraction-of-occurrences of two constituents isotopes is equal to one.

$f_{113} + f_{115} = 1\\f_{113} = 1- f_{115}$ ---------(2)

Substituting the given values in equation 1, we get

$^{115}In_w = f_{113}*A_{113} + f_{115}*A_{115}\\114.818 = (1 - f_{115}) * 112.904 + f_{115} * 114.904\\f_{115} = 0.957$

Substituting this value in equation 2 we get -

$f_{113} = 1- f_{115}\\f_{113} = 1- 0.957 \\f_{113} = 0.043$

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