You answer is $3.07 hope this helps. can i get brainliest?
An isosceles triangle has congruent base angles, so if one of the base angles measure 54 degrees, then the other base angle does, too.
And a triangle measures up to 180 degrees.
180 = x + 2(54)
180 = x + 108
x = 72
So the answer is B) 72
So there where two times the amount of rock tickets sold than the jazz concert. If that is it then you divide the 1840 by 2 getting 920, dividing 1÷2 you get zero remainder 1, 18÷2= 9, 4÷2= 2, and 0÷2= 0. 920. Hope i helped :)
Check the picture below.
so we know the radius of the semicircle is 2 and the rectangle below it is really a 4x4 square, so let's just get their separate areas and add them up.
![\stackrel{\textit{area of the semicircle}}{\cfrac{1}{2}\pi r^2}\implies \cfrac{1}{2}(\stackrel{\pi }{3.14})(2)^2\implies 3.14\cdot 2\implies 6.28 \\\\\\ \stackrel{\textit{area of the square}}{(4)(4)}\implies 16 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{sum of both areas}}{16+6.28=22.28}~\hfill](https://tex.z-dn.net/?f=%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20semicircle%7D%7D%7B%5Ccfrac%7B1%7D%7B2%7D%5Cpi%20r%5E2%7D%5Cimplies%20%5Ccfrac%7B1%7D%7B2%7D%28%5Cstackrel%7B%5Cpi%20%7D%7B3.14%7D%29%282%29%5E2%5Cimplies%203.14%5Ccdot%202%5Cimplies%206.28%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20square%7D%7D%7B%284%29%284%29%7D%5Cimplies%2016%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20%5Cstackrel%7B%5Ctextit%7Bsum%20of%20both%20areas%7D%7D%7B16%2B6.28%3D22.28%7D~%5Chfill)
7 3/10 + 6 1/3 + 2 7/10
First change them to improper fractions
73/10 + 19/3 + 27/10
now find the common denominator which would be 30
73/10 = 219 /30
19/3 = 190/30
27/10 = 81 /30
now add (219 + 190 + 81) = 490/30
now divide 490 ÷ 30 = 16 1/3
Your answer is 16 1/3
Hope this helps. :)
