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enyata [817]
3 years ago
6

A: 28, 23,30, 25, 27

Mathematics
1 answer:
Serggg [28]3 years ago
6 0

Answer:

8

Step-by-step explanation:

mean of A=28+23+30+25+27/5 = 26.6

average of B=22+19+15+17+20/5 = 18.6

now,

difference= 26.6-18.6

=8,,

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What is the inverse of the function h(x)=5+x/4-2x
deff fn [24]

Answer:

I believe you, Divide x x by 1 1 .

Step-by-step explanation:

Since g(h(x))=x g ( h ( x ) ) = x , h−1(x)=2x5−85 h - 1 ( x ) = 2 x 5 - 8 5 is the inverse of h(x)=52x+4 h ( x ) = 5 2 x + 4 .

sorry if im wrong

4 0
3 years ago
Find the answer for x​
Ber [7]

Answer:

I think the answer is 75.

Step-by-step explanation:

because 35 + 70 is equal to 105. So now we will just subtract 105 by 180. which will give us 75.

5 0
3 years ago
Find the area between the curves x=-2,x=3,y=4x,y=x-5
mixas84 [53]
Those are all lines...

So the x interval is from -2 to 3, because of x=-2 and x=3

The upper line is y(u)=4x and the lower line is y(l)=x-5

So the area between the two lines is:

A=⌠y(u)-y(l) dx

A=⌠4x-x+5 dx

A=⌠3x+5 dx

A=[3x^2/2+5x]

A=[(3x^2+10x)/2], x=[-2,3]

A=(1/2)(27+30-(12-20))

A=(1/2)(57+8)

A=(1/2)(65)

A=32.5 u^2
5 0
3 years ago
Which of the following is the solution
stealth61 [152]

|x|-2\leq -3

so|x|\leq -1 (this is wrong because |x|\geq 0 )


6 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Kitty [74]

Answer:   (-2, 5) and (2, -3)

<u>Step-by-step explanation:</u>

Graph the line y = -2x + 1 (which is in y = mx + b format) by plotting the y-intercept (b = 1) on the y-axis and then using the slope (m = -2) to plot the second point by going down 2 and right 1 unit from the first point:

        y - intercept = (0, 1)            2nd point = ( -1, 1).

Graph the parabola y = x² - 2x - 3 by first plotting the vertex and then plotting the y-intercept (or some other point):

y = x^2-2x-3\quad \rightarrow \quad a=1,\ b=-2,\ c=-3\\\\\text{axis of symmetry:}\ x = \dfrac{-b}{2a}\ \longrightarrow \ x=\dfrac{-(-2)}{2(1)}=\dfrac{2}{2}=1\\\\\text{y-value of vertex:}\ f(1) = (1)^2-2(1)-3\quad \longrightarrow \quad y = 1 - 2 - 3=-4\\\\\text{y-intercept:}\ f(0)= (0)^2-2(0)-3\ \longrightarrow \ y=0 - 0 - 3 = -3 \\

         vertex = (1, -4)                2nd point (y-intercept) = (0, -3)


<em>see attached</em> - the graphs intersect at two points:  (-2, 5) and (2, -3)


8 0
3 years ago
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