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vova2212 [387]
3 years ago
15

The question is in the photo.​

Physics
1 answer:
quester [9]3 years ago
6 0

Answer:

heyaa thereeee

see temperature is rising in interval of

0 to 4 minutes

8 to 10 minutes

but 8 to 10 is NOT in options

so answer is option a) 0 to 4 minutes

:))))

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Is a bath tub renewable or not?
Irina18 [472]
The water being poured into the bathtub is renewable and can be recycled, filtered, and renewed. But, metaphorically, each time you use electricity you drain a little water from the "bathtub" or the electric grid.
6 0
3 years ago
Read 2 more answers
Anne has a sample of a substance. Its volume is 20 cm3, and its mass is 100 grams. What is the sample’s density?
AveGali [126]

Answer:

density = 5000 [kg/m^3]

Explanation:

Density is defined as the relationship between mass and volume.

Now we have:

m = 100 [gr] = 0.1[kg]

V = volume = 20[cm^3]

20[cm^{3}]*1[\frac{m^{3} }{100^{3} cm^{3} } ] = 2*10^{-5}[m^{3} ]

density = 0.1 / (2 x 10^-5)

density = 5000 [kg/m^3]

7 0
4 years ago
When a car's starter is in use, it draws a large current. The car's lights draw much less current. As a certain car is starting,
ad-work [718]

Answer:

EMF = 11.35 V

R = 0.031Ω

Explanation:

To find the battery's EMF and the internal resistance we need to use Ohm's law:

V = IR

Where:

V: is the voltage

I: is the current

R is the resistance

We have:

The current through the battery is 64.2 A and the potential difference across the battery terminals is 9.36 V:

\epsilon = V + IR      

\epsilon = 9.36 V + 64.2A*R   (1)

When only the car's lights are used, the current through the battery is 1.96 A and the terminal potential difference is 11.3 V:

\epsilon = 11.3 V + 1.96A*R   (2)

By solving equation (1) and (2) for R we have:

9.36 V + 64.2A*R = 11.3 V + 1.96A*R

R = \frac{1.94 V}{62.24A} = 0.031 \Omega

Hence, the internal resistance is 0.031 Ω.

Now, by entering R into equation (1) we can find the battery's EMF:

\epsilon = 9.36 V + 64.2A*0.031 \Omega

\epsilon = 11.35 V

Therefore, the battery's EMF is 11.35 V.

I hope it helps you!                

8 0
4 years ago
The isotope used to remove cancer malignancy cell​
cupoosta [38]

Answer:

Yttrium-90 is used for treatment of cancer, particularly non-Hodgkin's lymphoma and liver cancer, and it is being used more widely, including for arthritis treatment. Lu-177 and Y-90 are becoming the main RNT agents. Iodine-131, samarium-153, and phosphorus-32 are also used for therapy.

Explanation:

paki follow and pa thanks naman lods :)

6 0
3 years ago
Each of 100 identical blocks sitting on a frictionless surface is connected to the next block by a massless string. The first bl
o-na [289]

Answer:

The tension in the string connecting block 50 to block 51 is 50 N.

Explanation:

Given that,

Number of block = 100

Force = 100 N

let m be the mass of each block.

We need to calculate the net force acting on the 100th block

Using second law of newton

F=ma

100=100m\times a

ma=1\ N

We need to calculate the tension in the string between blocks 99 and 100

Using formula of force

F_{100-99}=ma

F_{100-99}=1

We need to calculate the total number of masses attached to the string

Using formula for mass

m'=(100-50)m

m'=50m

We need to calculate the tension in the string connecting block 50 to block 51

Using formula of tension

F_{50}=m'a

Put the value into the formula

F_{50}=50m\times a

F_{50}=50\times1

F_{50}=50\ N

Hence, The tension in the string connecting block 50 to block 51 is 50 N.

8 0
4 years ago
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