Question

Young's double slit experiment is one of the quintessential experiments in physics. The availability of low cost lasers in recent years allows us to perform the double slit experiment rather easily in class. Your professor shines a green laser (568 nm) on a double slit with a separation of 0.112 mm. The diffraction pattern shines on the classroom wall 3.5 m away. Calculate the fringe separation between the second order and central fringe.

Answer 1

Answer:

Y = 17.75 x 10⁻³ m = 17.75 mm

Explanation:

Using Young's Double Slit formula below:

$Y = \frac{\lambda L}{d}$

where,

Y = fringe separation = ?

λ = wavelength = 568 nm = 5.68 x 10⁻⁷ m

L = distance between slits and screen = 3.5 m

d = slit separation = 0.112 mm = 1.12 x 10⁻⁴ m

Therefore,

$Y = \frac{(5.68\ x\ 10^{-7}\ m)(3.5\ m)}{1.12\ x\ 10^{-4}\ m}$

Y = 17.75 x 10⁻³ m = 17.75 mm