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Rashid [163]
1 year ago
10

Pls help me with a physics question I am struggling

Physics
1 answer:
konstantin123 [22]1 year ago
7 0

Answer:

It will condese to 47

Explanation:

As per as the table chart , Substance G melting point at 47 and boiling point at 120 so AS per as the chart

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A 8.8 cm diameter circular loop of wire is in a 1.04 T magnetic field. The loop is removed from the field in 0.30 s . Assume tha
denis23 [38]

Answer:

0.021 V

Explanation:

The average induced emf (E) can be calculated usgin the Faraday's Law:

E = - \frac{N*\Delta \phi}{\Delta t}  

<u>Where:</u>

<em>N = is the number of turns = 1   </em>

<em>ΔΦ = ΔB*A                                            </em>

<em>Δt = is the time = 0.3 s   </em>

<em>A = is the loop of wire area = πr² = πd²/4 </em>

<em>ΔB: is the magnetic field = (0 - 1.04) T                     </em>

Hence the average induced emf is:

E = - \frac{\Delta B*A}{\Delta t} = - \frac{(0- 1.04 T) \pi (0.088 m)^{2}}{4*0.3 s} = 0.021 V                      

Therefore, the average induced emf is 0.021 V.

I hope it helps you!

8 0
3 years ago
Which of the following is NOT part of a circuit?
uysha [10]
I believe it’s a. Rim
5 0
3 years ago
P= F/A make a the subject
lawyer [7]

Answer:

a=f/p

Explanation:

p=f/a

f=p×a

this all

4 0
3 years ago
The SI units for momentum are: Question 3 options: mph Newtons kg*m/s lbs*mph
Lunna [17]
The SI unit for momentum is kg*(m/s)
4 0
4 years ago
Read 2 more answers
A hot-air balloon is 11.0 m above the ground and rising at a speed of 7.00 m/s. A ball is thrown horizontally from the balloon b
Nesterboy [21]

Answer:

18.6 m/s

Explanation:

h = Initial height of the balloon = 11 m

v_{o} = initial speed of the ball

v_{oy} = initial vertical speed of the ball = 7 m/s

v_{ox} = initial horizontal speed of the ball = 9 m/s

initial speed of the ball is given as

v_{o} = \sqrt{v_{ox}^{2} + v_{oy}^{2}} = \sqrt{9^{2} + 7^{2}} = 11.4 m/s

v_{f} = final speed of the ball as it strikes the ground

m = mass of the ball

Using conservation of energy

Final kinetic energy before striking the ground = Initial potential energy + Initial kinetic energy

(0.5) m v_{f}^{2} = (0.5) m v_{o}^{2} + mgh \\(0.5) v_{f}^{2} = (0.5) v_{o}^{2} + gh\\(0.5) v_{f}^{2} = (0.5) (11.4)^{2} + (9.8)(11)\\(0.5) v_{f}^{2} = 172.78\\v_{f} = 18.6 m/s

7 0
3 years ago
Read 2 more answers
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