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hichkok12 [17]
3 years ago
6

An ideal gas in a balloon is kept in thermal equilibrium with its constant-temperature surroundings. How much work is done if th

e outside pressure is slowly reduced, allowing the balloon to expand to 50 times its original size
Physics
1 answer:
andreev551 [17]3 years ago
5 0

Answer:

w = 252.32 N

Explanation:

given data

balloon expand = 50 times its original size

we consider here  initially pressure and volume

pressure = 645 pa

volume = 0.10 m³

solution

as in isothermala process ideal gas

PV = mRT

P = \frac{mRT}{v}

P = \frac{c}{v}

here c is constant

so work done is express as

w = c \int\limits^{V2}_{V1} {\frac{dv}{v}}  

w = c \times ln( \frac{v2}{v1})

and we know c  = p1 × v1

so

w = p1 × v1 × ln (\frac{50v1}{v1} )

w = 645 × 0.1 × ln(50)

w = 252.32 N

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