Write an equation of the line that is parallel to the given line and passes through the given point.
1 answer:
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Answer:
see explanation
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
(1)
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (2, 22) and (x₂, y₂ ) = (4, 32) ← 2 ordered pairs from the table
m = =
= 5, thus
y = 5x + c ← is the partial equation
To find c substitute any ordered pair from the table into the partial equation
Using (6, 42), then
42 = 30 + c ⇒ c = 42 - 30 = 12
Thus Table 1 has slope = 5 and y- intercept = 12
(2)
Using (x₁, y₁ ) = 2, 15) and (x₂, y₂ ) = (1,8) ← 2 ordered pairs from the table
m = =
= 7, thus
y = 7x + c ← is the partial equation
To find c substitute (3, 22) into the partial equation
22 = 21 + c ⇒ c = 22- 21 = 1
Thus Table 2 has slope = 7 and y- intercept = 1
Answer:
60.65
Step-by-step explanation:
The Law of Cosines can help you figure this out. Call the given sides "a" and "b" and the given angle "C". Then the third side, "c" will satisfy the relation ...
c² = a² + b² -2ab·cos(C)
= 33² +37² -2·33·37·cos(120°) = 3679
c = √3679 ≈ 60.65476 ≈ 60.65
The length of the third side is about 60.65 units.
