What is the maximum number of electrons in the following energy level?<br> n = 4

The form of EMR that has less energy per photon than microwaves is ____?

Gala2k [10]

Answer: radio wave frequencies have longer wavelengths and smaller

Energies per photon

4 0

3 years ago

The physical matter of which living or nonliving things are composed is called a ___

kolezko [41]

Answer:

Substance

Explanation:

Any physical matter despite of living or non living things are composed by a set of molecules or atoms commonly known as substance

On specific living things are composed of biomolecules or cells where as non living things are composed of molecules and atoms

3 0

2 years ago

Easy points !<br> What was the problem with the Dalton model of the atom?

Yuliya22 [10]

The indivisibility of an atom was proved wrong: an atom can be further subdivided into protons, neutrons and electrons.

3 0

3 years ago

In the first step of the Ostwald process for the synthesis of nitric acid, ammonia is converted to nitric oxide by the high-temp

Paul [167]

Solution: The given balanced equation is:

$4NH_3+5O_2\rightarrow 4NO+6H_2O$

If we have a hypothetical equation:

$A+2B\rightarrow 3C+5D$

Then the rate could be written as:

$rate=-\frac{\Delta [A]}{\Delta t}=-\frac{1}{2}\frac{\Delta [B]}{\Delta t}=\frac{1}{3}\frac{\Delta [C]}{\Delta t}=\frac{1}{5}\frac{\Delta [D]}{\Delta t}$

From above expression one thing could easily be noticed that the coefficients of all are inverted. Also, there is negative sign in front of reactants and positive sign in front of the products. Negative sign stands for rate of consumption where as positive sign stands for rate of formation.

Like the above example, we can write the rate for the given equation and it would be looking as:

$rate=-\frac{1}{4}\frac{\Delta [NH_3]}{\Delta t}=-\frac{1}{5}\frac{\Delta [O_2]}{\Delta t}=\frac{1}{4}\frac{\Delta [NO]}{\Delta t}=\frac{1}{6}\frac{\Delta [H_2O]}{\Delta t}$

Now we can easily answer all the parts of the question.

(a) From above expression, the rate of consumption of $O_2$ related to rate of consumption of $NH_3$ as:

$-\frac{1}{5}\frac{\Delta [O_2]}{\Delta t}=-\frac{1}{4}\frac{\Delta [NH_3]}{\Delta t}$

multiply both sides by -5

$\frac{\Delta [O_2]}{\Delta t}=\frac{5}{4}\frac{\Delta [NH_3]}{\Delta t}$

So, rate of consumption of oxygen is $\frac{5}{4}$ the rate of consumption of ammonia.

(b) The relationship between rate of formation of NO to the rate of consumption of ammonia will be written as:

$\frac{1}{4}\frac{\Delta [NO]}{\Delta t}=-\frac{1}{4}\frac{\Delta [NH_3]}{\Delta t}$

Multiply both sides by 4

$\frac{\Delta [NO]}{\Delta t}=-\frac{\Delta [NH_3]}{\Delta t}$

So, rate of formation of NO equals to the rate of consumption of ammonia.

Now, the rate of formation of $H_2O$ to the rate of consumption of ammonia would be:

$\frac{1}{6}\frac{\Delta [H_2O]}{\Delta t}=-\frac{1}{4}\frac{\Delta [NH_3]}{\Delta t}$

Multiply both sides by 6

$\frac{\Delta [H_2O]}{\Delta t}=-\frac{6}{4}\frac{\Delta [NH_3]}{\Delta t}$

So, the rate of formation of $H_2O$ is $\frac{6}{4}$ times that is 1.5 times to the rate of consumption of ammonia.

5 0

4 years ago

An atom of oxygen has six valence electrons. In nature, oxygen is a diatomic molecule and is usually found in the form O2. Why w

zheka24 [161]

Answer:

In order to attain stability

Explanation:

Every chemical bonds that are formed results from the desires of atoms to achieve stability like the inert and nonreactive noble gases. By so doing, their outer shell electrons must be completely filled to attain an octet configuration like the noble gases with eight outermost electrons.

An atom of oxygen has six outer electrons. To complete its octet, it will require just two more electrons.

This desire will make it bond with another atom. In the vicinity of another oxygen atom, it will bond. The type of bond formed will be a covalent bond which results from each of the oxygen atom sharing two of their valence electrons.

The joint shared electrons will now be four electrons. This four electrons will make each of their octet complete and a covalent bond occurs.

3 0

3 years ago

What is the maximum number of electrons in the following energy level? n = 4