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Sedbober [7]
1 year ago
5

If you start with 3 moles of sodium and 3 moles of chlorine to produce sodium chloride, what is the limiting reagent?(you will n

eed to balance the equation first.) na cl2 -> nacl
Chemistry
1 answer:
Harman [31]1 year ago
4 0

Sodium(Na) is the limiting reagent.

<h3>What is Limiting reagent?</h3>

The reactant that is totally consumed during a reaction, or the limiting reagent, decides when the process comes to an end. The precise quantity of reactant required to react with another element may be estimated from the reaction stoichiometry.

How do you identify a limiting reagent?

The limiting reactant is the one that is consumed first and sets a limit on the quantity of product(s) that can be produced. Calculate how many moles of each reactant are present and contrast this ratio with the mole ratio of the reactants in the balanced chemical equation to get the limiting reactant.

Start by writing the balanced chemical equation that describes this reaction

2Na_{(s)} + Cl_{2 (g)} -- > 2NaCl_{(s)}

Notice that the reaction consumes 2 moles of sodium metal for every 1 mole of chlorine gas that takes part in the reaction and produces 2 moles of sodium chloride.

now we can see that we have 3 moles of sodium and 3 moles of chlorine, according to question. so, we can say that sodium is the limiting reagent in the given situation.

to learn more about Limiting Reagent go to - brainly.com/question/14222359

#SPJ4

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If you have a 150-gram sample of CrO3: • How many moles of CrO3 do you have? • How many oxygen atoms do you have? • How many gra
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Answer :

(a) The moles of CrO_3 is, 1.5 moles.

(b) The number of oxygen atoms are, 27.099\times 10^{23}

(c) The mass of oxygen is, 72 grams.

Explanation : Given,

Mass of CrO_3 = 150 g

Molar mass of CrO_3 = 100 g/mole

Molar mass of oxygen = 16 g/mole

(a) First we have to calculate the moles of CrO_3.

\text{Moles of }CrO_3=\frac{\text{Mass of }CrO_3}{\text{Molar mass of }CrO_3}=\frac{150g}{100g/mole}=1.5moles

The moles of CrO_3 is, 1.5 moles.

(b) Now we have to calculate the number of oxygen atoms.

In CrO_3, there are 1 atom of chromium and 3 atoms of oxygen.

According to the mole concept,

1 mole of CrO_3 contains 3\times 6.022\times 10^{23} number of oxygen atoms.

So, 1.5 mole of CrO_3 contains 1.5\times 3\times 6.022\times 10^{23}=27.099\times 10^{23} number of oxygen atoms.

The number of oxygen atoms are, 27.099\times 10^{23}

(c) Now we have to calculate the mass of oxygen.

As, 1 mole of CrO_3 contains 3 moles of oxygen

So, 1.5 mole of CrO_3 contains 1.5\times 3=4.5 moles of oxygen

\text{Mass of oxygen}=\text{Moles of oxygen}\times \text{Molar mass of oxygen}

\text{Mass of oxygen}=(4.5mole)\times (16g/mole)=72g

The mass of oxygen is, 72 grams.

3 0
3 years ago
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