Answer:
58.94 mL
Explanation:
V1 = 48.3 mL V2 = v mL
T1 = 22 degree celsius OR 295 k T2 = 87 degree celsius OR 360 k
We will use the gas equation:
PV = nRT
Since the Pressure (p) , number of moles (n) and the universal gas constant(R) are all constants in this given scenario,
we can say that
V / T = k , (where k is a constant)
Since this is the first case,
V1 / T1 = k --------------------(1)
For case 2:
Since we have the same constants, the equation will be the same
V / T = k (where k is the same constant from before)
V2 / T2 = k (Since this is the second case) ------------------(2)
From (1) and (2):
V1 / T1 = V2 / T2
Now, replacing the variables with the given values
48.3 / 295 = v / 360
v = 48.3*360 / 295
v = 58.94 mL
Therefore, the final volume of the gas is 58.94 mL
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Answer:

Explanation:
The graduated cylinder contains
of water
mL is a volume unit.
Water volume = 41.7 mL
The lead ball caused an increase of volume from 41.7 mL to 96.0 mL
The new volume is the lead ball volume plus the original water volume :
Final volume = Vlead ball+ Water original volume



This is actually true if we suppose that the lead ball is fully sunken in the water.
We always must consider that the volume difference is the volume that the sunken object is occupying in the water.
Answer: 0.036 J/g°C
Explanation:
The quantity of heat energy (Q) required to raise the temperature of a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)
Thus, Q = MCΦ
Given that,
Q = 3.42 Kilojoules
[Convert 3.42 kilojoules to joules
If 1 kilojoule = 1000 joules
3.42 kilojoules = 3.42 x 1000 = 3420J]
Mass = 2.508Kg
[Convert 2.508 kg to grams
If 1 kg = 1000 grams
2.508kg = 2.508 x 1000 = 2508g]
C = ? (let unknown value be Z)
Φ = (Final temperature - Initial temperature)
= 42.061°C - 4.051°C
= 38.01°C
Apply the formula, Q = MCΦ
3420J = 2508g x Z x 38.01°C
3420J = 95329.08g•°C x Z
Z = (3420J / 95329.08g•°C)
Z = 0.03588 J/g°C
Round the value of Z to the nearest thousandth, hence Z = 0.036 J/g°C
Thus, the specific heat of the substance is 0.036 J/g°C