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balu736 [363]
4 years ago
10

A redox reaction has occurred ________.

Chemistry
1 answer:
mart [117]4 years ago
7 0

Answer : The correct option is, (a) when a substance reacts with elemental oxygen.

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

From the given options we conclude that a redox reaction has occurred  when a substance reacts with elemental oxygen. Because elemental oxygen will oxidize the metal and itself get reduced. Thus, it is a redox reaction.

For example :

Mg+O_2\rightarrow MgO

This reaction is a redox reaction in which magnesium shows oxidation due to change in oxidation state from (0) to (+2) and oxygen shows reduction due to change in oxidation state from (0) to (-2).

Hence, the correct option is, (a) when a substance reacts with elemental oxygen.

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4.62 ) (a) Calculate the molarity of a solution made by dissolving 12.5 grams of Na2CrO4 in enough water to form exactly 750 mL
Gelneren [198K]

Answer:

a. [Na₂CrO₄] = 0.10 M

b. 0.017 moles of KBr

Explanation:

Molarity means a sort of concentration which indicates the moles of solute over 1L of solution.

We determine the moles of solute: 12.5 g / 162g/mol = 0.0771 moles

We convert the volume of solution from mL to L = 750 mL . 1L/1000mL = 0.750L

Molarity (mol/L) → 0.0771 mol / 0.750L = 0.10 M

b. In order to determine the moles of solute, with the molarity of solution and the volume we assume:

Molarity = moles of solute /volume of solution

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We convert the volume of solution from mL to L = 150 mL . 1L/1000mL = 0.150L

0.112 mol/L . 0.150L = Moles of solute → 0.017 moles of KBr

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