Answer:
A
Step-by-step explanation:
i think so..sorry if im wrong
f(0)=64, f(1)=66, f(2)=72, f(3)=82, f(4)=96,...=2,6,10,14,...=2{1,3,5,7,...}
This can be written 2{2x+1}, so the intervals on which f(x) increases are 4x+2.
It is just the multiplication of vectors. We'll multiply corresponding pairs together. The general formula for the pairs of (

;

) and (

;

) is

*

+

*

= (-6)*(-3)+4*6=18+24=42
The answer is
-5 IS NOT in the domain of fog
Answer:
Step-by-step explanation:
This kinda looks like the limiting definition of a derivative.
Anyway, what we are doing with the f(2 + h) is evaluating f(x) with 2+h in place for x. That looks like this:
f(2 + h) = 2(2 + h) - 3 which simplifies to
f(2 + h) = 4 + 2h - 3 which simplifies to
2h + 1
From that we are subtracting f(2). What we are doing with that is evaluating f(x) with 2 in place for x. That looks like this:
f(2) = 2(2) - 3 which simplifies to
f(2) = 4 - 3 which simplifies to
f(2) = 1. Now put those together over h to get:
