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2 years ago

8th grade math

Mathematics

2 answers:

UkoKoshka [18]2 years ago

6 0

Answer:

10 Milk chocolates

8 dark chocolates

6 white chocolates

24 TOTAL

\frac{10}{24} Probability that Hanissa choose a milk chocolate

Now, since she has already eaten one chocolate, then what's left is 23 chocolates.

So, since the second one should be a white chocolate and there are 6 of them, then

\frac{6}{23} - probability of choosing a white chocolate.

Then, multiply,

( \frac{10}{24} )( \frac{6}{23} )= \frac{60}{552} or \frac{5}{46}

Answer: 5/46 or 10.87%

Step-by-step explanation:

Vlad1618 [11]2 years ago

3 0

Answer: there is 1/2 chance of your first being milk chocolate, 1/3 chance your second will be drake and 1/6 chance it will be white chocolate

Step-by-step explanation:

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The claim to be tested is:

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To test this claim the hypothesis can be defined as follows:

H₀: The mean respiration rate of students is 32, i.e. μ = 32.

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