The value of x is 15.56.
Solution:
Tangent and Secant theorem:
If one secant and one tangent are drawn to a circle from one exterior point, then the square of the length of the tangent is equal to the product of the external secant segment and the total length of the secant.
BE = 22 BD = x, CD = x
BC = x + x = 2x
By the tangent and secant theorem,



Divide by 2 on both sides of the equation, we get

Take square root on both side of the equation.
x = 15.56
Hence the value of x is 15.56.
The sign of the leading coefficient can be found using the graph of a polynomial function.
<h3>What is polynomial?</h3>
Polynomial is the combination of variables and constants systematically with "n" number of power in ascending or descending order.

We have given the graph of polynomial functions:
In the first graph:
The leading coefficient is positive.
x → ∞, f(x) → ∞
x → -∞, f(x) → -∞
Degree of a function = 3
In the second graph:
The leading coefficient is negative.
x → ∞, f(x) → -∞
x → -∞, f(x) → -∞
Degree of a function = 4
In the third graph:
The leading coefficient is positive.
x → ∞, f(x) → ∞
x → -∞, f(x) → ∞
Degree of a function = 4
In the fourth graph:
The leading coefficient is negative.
x → ∞, f(x) → -∞
x → -∞, f(x) → ∞
Degree of a function = 3
Thus, the sign of the leading coefficient can be found using the graph of a polynomial function.
Learn more about Polynomial here:
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6.4 is the sqaure root of 42 youre welcome!
Answer: A. 42 tickets
Step-by-step explanation: 8, 16, 24, 32, 40, 48
AAS Postulate
It is given that CE = BD so we know "S" (representing side) has to be in the three letter postulate.
It is also given that angle DBA and angle CEA are right angles, so therefore they are congruent. Now we know that an "A" must also be in the postulate.
Lastly, we know that the triangles have a second angle, EAB, in common because they share it overlappingly. So there must be another "A" in the postulate.
Now we need to look at the order in which it is presented. The order follows Angle, Angle, Side so the postulate must be the AAS postulate. Hope this helps!