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Llana [10]
3 years ago
11

Where is the error in the solution below? Explain what the error is and solve the equation correctly. Be sure to check your answ

er.

Mathematics
2 answers:
ANTONII [103]3 years ago
6 0

Answer:

The error in the question is that in the second line, both sides are not multiplied by x. This causes an imbalance in the equation.

Step-by-step explanation:

\frac{5}{x}= x-4

Multiply both sides by x.

x(\frac{5}{x}) = x(x-4)

5= x^{2} -4x

Subtract 5 from the equations.

x^{2} -4x-5=0

Factorise the equation (Quadratics)

(x-5)(x+1)=0

Null Factor Law

x=5 or x=-1

Sunny_sXe [5.5K]3 years ago
3 0

Answer:

Where is the error in the solution below? Explain what the error is and solve the equation correctly. Be sure to check your answer.

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Which are sums of perfect cubes? Check all that apply. 8x6 27 x9 1 81x3 16x6 x6 x3 27x9 x12 9x3 27x9.
Black_prince [1.1K]

The equations which are sums of perfect cubes are as follows;

\rm 8x^6+27x^9+1

\rm x^6+x^3

\rm 27x^9+x^{12}

<h3>Perfect cubes;</h3>

Perfect cubes are the numbers that are the triple product of the same number.

We have to determine

Which are sums of perfect cubes?

1. The given equation is \rm 8x^6+27x^9+1.

The equation can be written as;

\rm 8x^6+27x^9+1\\\\2^3(x^2)^3+3^3(x^3)^3+1^3

All the terms in the expression are can be represented as perfect cubes.

2.  The given equation is \rm 81x^3+16x^6.

The equation can be written as;

\rm 81x^3+16x^6\\\\9^2x^3+4^2(x^2)3

In this, all the terms are not perfect cubes, some of them are squares.

3. The given equation is \rm x^6+x^3.

The equation can be written as;

\rm x^6+x^3\\\\(x^2)^3+x^3

All the terms in the expression are perfect cubes.

4.  The given equation is \rm 27x^9+x^{12}.

The equation can be written as;

\rm 27x^9+x^{12}\\\\3^3(x^3)^3+(x^4)^3

All the terms in the expression are perfect cubes.

5.   The given equation is \rm 9x^3+27x^9.

The equation can be written as;

\rm 9x^3+27x^9\\\\3^2x^3+3^3(x^3)^3

In this, all the terms are not perfect cubes, some of them are squares too.

To know more about perfect cubes click the link given below.

brainly.com/question/4701925

5 0
2 years ago
Read 2 more answers
What is the diameter of a circle with a circumfrence of 8 centimeters??
rjkz [21]

Answer:

2.547

Step-by-step explanation:

2pir=8

1.273=r

d=2r

2.547=d

5 0
3 years ago
Please I am on a timer
Mila [183]

Answer: g=5

Step-by-step explanation:

4 0
3 years ago
Factor 64v^3 + 192v^2 -56v - 168​
Kaylis [27]

Hello from MrBillDoesMath!

Answer:

8(v+3) ( -1/2 (sqrt(14) - 4 v) (4 v + sqrt(14)) )


Discussion:

Given

64v^3 + 192v^2 - 56 v - 168      

Factor 64v^2 from the first two terms. Factor 56 from the last two terms:

64v^2(v+3) - 56(v  + 3)     => factor (v+3) from both terms

(v+3) (64v^2 - 56)             => factor 8 from both terms in the right ()

8(v+3)(8v^2-7)                   => factor 8y^2-7

8(v+3) ( -1/2 (sqrt(14) - 4 v) (4 v + sqrt(14)) )



Thank you,

MrB

4 0
3 years ago
V is themidpoint of UW. If UV = x + 8 and VW = 9x, what is VW?
user100 [1]

Answer:

x=1

Step-by-step explanation:

If V is the midpoint of the line UW, that would mean that there's an equal distance between UV and 9x. So, the value of UV and VW would eed to be the same.

x+8=9x

8=8x

x=1

8 0
2 years ago
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