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White raven [17]
3 years ago
12

A student has a block that has a volume of 150 cm3 and a density of 30 g/cm3

Physics
1 answer:
dlinn [17]3 years ago
3 0

Answer:

mass of block = 4500g

Explanation:

density = mass/volume

mass = volume x density

         = 150 x 30

         = 4500 g

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A recent home energy bill indicates that a household used 475475 kWh (kilowatt‑hour) of electrical energy and 135135 therms for
faltersainse [42]

Answer:

Explanation:

Given that,.

A house hold power consumption is

475 KWh

Gas used is

135 thermal gas for month

Given that, 1 thermal = 29.3 KWh

Then,

135 thermal = 135 × 29.3 = 3955.5 KWh

So, total power used is

P = 475 + 3955.5

P =4430.5 KWh

Since 1 hr = 3600 seconds

So, the energy consumed for 1hr is

1KW = 1000W

P = energy / time

Energy = Power × time

E = 4430.5 KWhr × 1000W / KW × 3600s / hr

E = 1.595 × 10^10 J

So, using Albert Einstein relativity equation

E = mc²

m = E / c²

c is speed of light = 3 × 10^8 m/s

m = 1.595 × 10^10 / (3 × 10^8)²

m = 1.77 × 10^-7 kg

Then,

1 kg = 10^6 mg

m = 1.77 × 10^-7 kg × 10^6 mg / kg

m = 0.177mg

m ≈ 0.18 mg

5 0
3 years ago
The diagram below shows the force exerted on object m1 due to the gravitational attraction between m1 and m2. What is true about
gladu [14]

Answer: B. It is directed to the left.

Explanation:

Gravitational force is an attractive force, this is stated by Newton's law of Gravitation:

<em>"The force exerted between two bodies of masses m1 and m2 and separated by a distance  is equal to the product of their masses and inversely proportional to the square of the distance"</em>

This means both m1 and m2 are mutually attracted.

Hence, if the force exerted on m1 by m2 is directed to the right, the force exerted on m2 by m1 must be logically <u>directed to the left.</u>

8 0
3 years ago
Pronouns in the nominative case may function as __________.
tresset_1 [31]

Pronouns in the nominative case may function as Subjects.

Like

We went to the game.
You played the game.
He/she/they watched the game.

8 0
3 years ago
A satellite orbits the Earth in the same direction it rotates in a circular orbit above the equator a distance of 250 km from th
UkoKoshka [18]

Answer:

Clock on the satellite is slower than the one present on the earth = 29.376 s

Given:

Distance of satellite from the surface, d = 250 km

Explanation:

Here, the satellite orbits the earth in circular motion, thus the necessary centripetal force is provided by the gravitation force and is given by:

\frac{mv^{2}}{R} = \frac{GMm}{R^{2}}

where

v =  velocity of the satellite

R = radius of the earth = 6350 km = 6350000 m

G = gravitational constant = 6.674\times 10^{- 11} m^{3}/ks-s^{2}

M = mass of earth = 5.972\times 10^{24} kg

Therefore, the above eqn can be written as:

v = \sqrt{\frac{GM}{R}}

Now, for relativistic effects:

\frac{v}{c} = \sqrt{\frac{GM}{Rc^{2}}} = 26.41\times 10^{- 6}

Now,

r = R + 250

\frac{v_{surface}}{c} = {\frac{1}{c}\frac{2\pi R}{24} = 1.54\times 10^{-6}

Ratio of rate of satellite clock to surface clock:

\frac{\sqrt{1 - \frac{v^{2}}{c^{2}}}}{\sqrt{1 - \frac{v_{surface}^{2}}{c^{2}}}} = 3.43\times 10^{-10}

Clock on the satellite is slower than the one present on the earth:

3.43\times 10^{-10}\times 24\times 3600 = 29.376 s

4 0
3 years ago
3. A sample of argon of mass 6.56 g occupies 18.5 dm? at 305 K. (a) Calculate the work done when the gas expands isothermally ag
aleksandr82 [10.1K]

Answer:

(a) W=-19.25J

(b) W=-52.8J

Explanation:

Hello.

(a) In this case, since the initial volume is 18.5 dm³ and the final volume is 21 dm³ (18.5 +2.5), we can compute the work at constant pressure as shown below:

W=-P\Delta V=-7.7kPa*\frac{1000Pa}{1kPa} (21dm^3-18.5dm^3)*\frac{1m^3}{1000dm^3}\\ \\W=-19.25J

Which is negative as it expands against the given pressure.

(b) Moreover, of the process is carried out reversibly, the pressure can change, therefore, we need to compute the work via:

W=nRTln(\frac{V_1}{V_2} )

Whereas the moles are computed from the given mass of argon:

n=6.56g*\frac{1mol}{39.95g}=0.164mol

Thus, the work is:

W=0.164mol*8.314\frac{J}{mol*K} *305Kln(\frac{18.5dm^3}{21dm^3} )\\\\W=-52.8J

Regards.

4 0
3 years ago
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