By using the equations for <em>parabolic</em> motion, we proceed to present the answers for the paragraph seen in the picture: a) t ≈ 0.553 s, b) s = 2.212 m, c) s = 11.060 m.
<h3>How to analyze a system on parabolic motion</h3>
A system is on <em>parabolic</em> motion if such system can be represented as a particle, that is, a system whose geometry is negligible, and its motion is a combination of <em>horizontal</em> movement at <em>constant</em> velocity and <em>vertical</em> <em>uniformly accelerated</em> movement due to gravity and all <em>viscous</em> and <em>rotational</em> effects are negligible.
The time required for the droplet to reach the ground is:
1.5 m = (1 / 2) · (9.807 m / s²) · t²
t = √[2 · (1.5 m) / (9.807 m / s²)]
t ≈ 0.553 s
And the <em>horizontal</em> distance traveled by the droplet is:
s = (4 m / s) · (0.553 s)
s = 2.212 m
Now, we apply the same procedure for the case of sneezing person:
1.5 m = (1 / 2) · (9.807 m / s²) · t²
t = √[2 · (1.5 m) / (9.807 m / s²)]
t ≈ 0.553 s
s = (20 m / s) · (0.553 s)
s = 11.060 m
To learn more on parabolic motion: brainly.com/question/16992646
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Image of the plate is missing, so i have attached it.
Answer:
A) t = 7.854 mm
B) σ = 26.67 MPa
Explanation:
A) From shearing of rivet, formula for pressure is;
P = τ•A_rivets
Where;
τ is allowable stress
A_rivets is Area of rivet
We are given:
τ = 60 MPa
Diameter; d = 20 mm
A_rivets = πd²/4 = π × 20²/4 = 100π
Thus;
P = 60 × 100π
P = 6000π N
From bearing of plate material, we can calculate pressure as;
P = σ_b•A_b
We are given;
σ_b = 120 MPa
A_b is area of plate = 20t
Where t is the thickness
Thus;
6000π = 120 × 20t
t = 6000π/(120 × 20)
t = 7.854 mm
B) Largest average tensile stress is given by the formula;
σ = P/A
Where A = 110t - 20t
A = 90t
A = 90 × 7.854
Thus;
σ = 6000π/(90 × 7.854)
σ = 26.67 MPa
<span>What's the speed of a sound wave through water at 25° Celsius?
<span> <span><span> <span>A. </span>1,250 m/s</span><span> <span>B. </span>1,500 m/s</span><span> <span>C. </span>750 m/s</span><span> <span>D. </span>1,000 m/s
</span></span></span></span>
<span>(a) 39.5 g
(b) 49.53 cm^3
(c) 0.7975 g/cm^3, liquid is an alcohol
(a) This will be the difference between the weight of the iron in air and the weight submerged in fluid. So:
390.0 g - 350.5 g = 39.5 g
(b) The density of iron is 7.874 g/cm^3, so the volume of the iron chunk is
390.0 g / 7.874 g/cm^3 = 49.53 cm^3
(c) The density of the fluid will be the mass of the fluid divided by the volume, so:
39.5 g / 49.53 cm^3 = 0.7975 g/cm^3
Since the density is very dependent upon the temperature and since the temperature wasn't specified, the actual substance can't be completely identified. Although some candidates are:
1. Mixture of Alcohol and water. Density ranges from 0.785 g/cm^3 to 1.000 g/cm^3.
2. Crude oil. Density 0.790 g/cm^3
3. Hydrazine. Density 0.795 g/cm^3
4. Methanol. Density 0.791 g/cm^3
5. Ocimene. Density 0.798 g/cm^3
The most likely candidate is a high concentration of an alcohol of some sort.</span>
