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4 years ago

The liquid pressure varies with depth why

Physics

1 answer:

Solnce55 [7]4 years ago

3 0

Explanation:

Hey, there!

The liquid pressure varies with depth because liquid pressure is directly proportional to the depth of liquid from the free surface of the liquid. so, more the depth more the pressure and less the depth less the pressure.

Hope it helps...

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Click to review the online content. Then answer the question(s) below, using complete sentences. Scroll down to view additional

Igoryamba

Answer:

Rococo art relates to an artistic style especially of the 18th century characterized by fanciful curved asymmetrical forms and elaborate ornamentation.

Explanation:

yes

6 0

3 years ago

Read 2 more answers

you are driving along a country road when you suddenly notice a log in the road ahead of you and immediately apply your brakes.

DiKsa [7]

a. The car will not hit the tractor.

b. The car would travel a distance of 52.07 m before stopping

c. At the moment when the car stopped, the tractor is 11.5 m in front of the car.

Linear motion

From the question, we are to determine of you will hit the tractor before you stop

First, we will determine the time it will take the car to stop

From the given information,

Initial velocity, u = 27.0 m/s

a = -7 m/s² (Negative sign indicates deceleration)

v = 0 m/s (Since the car will come to stop)

From one of the equations of linear motion,

v = u + at

Where v is the final velocity

u is the initial velocity

a is the acceleration

and t is the time taken

Putting the parameters into the equation, we get

0 = 27 + (-7)t

7t = 27

t = 27/7

t = 3.857 secs

This is the time it will take the car to stop

Now, we will determine the distance the car would travel after applying the brakes

Using the formula

S = (u + v) / t

Where S is the distance traveled

S = [(27 + 0) / 2] * 3.857

S = 13.5 * 3.857

S = 52.0695 m

S ≅ 52.07 m

This means the car would travel 52.07 m after applying the brakes

Now, we will determine the distance the tractor would have traveled when the car came to a stop

Speed of the tractor = 10.0 m/s

Time taken for the car to stop = 3.857 secs

Using the formula,

Distance = Speed × Time

Distance = 10.0 × 3.857

Distance = 38.57 m

Now, we will determine the distance between the car and the tractor when the car finally stopped

Distance between the car and the tractor = Distance ahead + Distance traveled by the tractor after the car stopped - Distance traveled by car after applying the brakes

Distance between the car and the tractor = 25 m + 38.57 m - 52.07 m

Distance between the car and the tractor = 11.5 m

Therefore, the distance the tractor was ahead of the car + the distance the tractor traveled after the car stopped is more than the distance the car traveled after applying the brakes (25 m + 38.57 m > 52.07), the car will not hit the tractor.

To know more about distance, refer: brainly.com/question/10903482

#SPJ4

[NOTE: THIS IS AN INCOMPLETE QUESTION. THE COMPLETE QUESTION IS: You are driving your car along a country road at a speed of 27.0 m/s. as you come over the crest of a hill, you notice a farm tractor 25.0 m ahead of you on the road, moving in the same direction as you at a speed of 10.0 m/s. you immediately slam on your brakes and slow down with a constant acceleration of magnitude 7.00 m/s2 .

a.will you hit the tractor before you stop?

b.how far will you travel before you stop or collide with the tractor?

c.if you stop, how far is the tractor in front of you when you finally stop?]

7 0

1 year ago

Calculate the density of Saturn. Show your work. How does it compare with the density of water? Explain how this can be.

stepladder [879]

Answer:

The density of Saturn is 686.81 kg/m³.

Explanation:

Mass of Saturn, $m=5.68\times 10^{26}\ kg$

Volume of Saturn, $V=8.27\times 10^{23}\ m^3$

Density of Saturn is given by its mass divided by its volume i.e.

$d=\dfrac{m}{V}$

$d=\dfrac{5.68\times 10^{26}}{8.27\times 10^{23}}$

$d=686.81\ kg/m^3$

So, the density of Saturn is 686.81 kg/m³.

The density of water is 1000 kg/m³. It is clear that the density of Saturn is less than water.

4 0

3 years ago

A superball with a mass m = 61.6 g is dropped from a height h = [02]____________________ m. It hits the floor and then rebounds

aleksklad [387]

There is not enough data to solve the problem, but I'm assuming the initial height as h = 10 m for the question to have a valid answer and the student can have a reference to solve their own problem

Answer:

(a) $\Delta P=1.67 \ kg.m/s$

(b) $\Delta P=0.86\ m/s$

Explanation:

Change of Momentum

The momentum of a given particle of mass m traveling at a speed v is given by

$P=m.v$

When this particle changes its speed to a value v', the new momentum is

$P'=m.v'$

The change of momentum is

$\Delta P=m.v'-m.v$

$\Delta P=m.(v'-v)$

Defining upward as the positive direction, we'll compute the change of momentum in two separate cases.

(a) The initial height of the superball of m=61.6 gr = 0.0616 Kg is set to h= 10 m. This information leads us to have the initial potential energy of the ball just after it's dropped to the floor:

$U=m.g.h=0.0616\cdot 9.8\cdot 10 =6.0368\ J$

This potential energy is transformed into kinetic energy just before the collision occurs, thus

$\displaystyle \frac{1}{2}mv^2=6.0368$

Solving for v

$\displaystyle v=\sqrt{\frac{6.0368\cdot 2}{0.0616}}$

$v=-14\ m/s$

This is the speed of the ball just before the collision with the floor. It's negative because it goes downward. Now we'll compute the speed it has after the collision. We'll use the new height and proceed similarly as above. The new height is

$h'=88.5\% (10)=8.85\ m$

The potential energy reached by the ball at its rebound is

$U'=m.g.h'=0.0616\cdot 9.8\cdot 8.85 =5.342568\ J$

Thus the speed after the collision is

$\displaystyle v'=\sqrt{\frac{5.342568\cdot 2}{0.0616}}$

$v'=13.17\ m/s$

The change of momentum is

$\Delta P=0.0616\cdot (13.17+14)$

$\Delta P=1.67 \ kg.m/s$

(b) If the putty sticks to the floor, then v'=0

$\Delta P=0.0616\cdot (0+14)$

$\Delta P=0.86\ m/s$

3 0

4 years ago

Your question: "the picture shows a professional diver with a mass of 93 kg from a 25 m high cliff. Earths Gravity is acting on

GuDViN [60]

When we see the words "Which statement ... ", we know right away that there
will be a list of choices, and we're expected to select our answer from that list.
Strangely, the list of answer-choices for this question has been lost.

Similarly, when we see the words "The picture shows ... ", it's hard to fight
the impulse to look around. In the present situation, that's missing too.

If the diver is just standing there, then the reaction force provided by the cliff
against his feet must be exactly equal to his weight. If the vertical forces acting
on the soles of his feet were not balanced, then his feet would be accelerating
vertically.

His weight is (mass) x (gravity) =

(93 kg) x (9.8 m/s²) = 911.4 newtons (about 205 pounds) .

That's also the strength of the upward reaction force provided by the cliff.

6 0

4 years ago

The liquid pressure varies with depth why​

The liquid pressure varies with depth why