<span>Income earned over one year is principal * int rate so we have
0.12*A + 0.13*B +0.14*C = 400
and A + B + C = 3000
and A+B = C</span>
Answer:
The distance from A to B is 736.2 to the nearest tenth foot
Step-by-step explanation:
In ΔCAB
∵ m∠CAD = 30° ⇒ exterior angle of Δ at vertex A
∴ m∠CAD = m∠ACB + m∠ABC
∵ m∠ABC = 20°
∴ m∠ACB = 30° - 20° = 10°
We will use the sin rule to find the distance AB
∵
∴ ≅ 736.2 to the nearest tenth foot
1 meter = 100 centimeters, so 120 centimeters equal to 1.2 meters.