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lesya692 [45]
3 years ago
6

A skydiver slows down from 65 m/s to 5 m/s by opening the parachute. If this

Chemistry
2 answers:
Cerrena [4.2K]3 years ago
8 0

Answer:

\boxed {\boxed {\sf D. \ 80 \ m/s^2 \ down}}

Explanation:

We are asked to find the acceleration of a skydiver. Acceleration is the change in velocity over the change in time, so the formula for calculating acceleration is:

a= \frac{v_f-v_i}{t}

The skydiver was initially traveling 65 meters per second, then he slowed down to a final velocity of 5 meters per second. He slowed down in 0.75 seconds.

\bullet \  v_f = 5 \ m/s \\\bullet \  v_i= 65 \ m/s \\\bullet \  t= 0.75 \ s

Substitute the values into the formula.

a= \frac{ 5 \ m/s - 65 \ m/s}{0.75 \ s}

Solve the numerator.

a= \frac{-60 \ m/s}{0.75 \ s}

Divide.

a= -80 \ m/s^2

The acceleration of the skydiver is <u>-80 meters per second squared</u> or <u>80 meters per second squared down</u>. The skydiver is slowing down or decelerating, so the acceleration is negative or down.

aivan3 [116]3 years ago
5 0

Answer:

D. -80m/s^2

Explanation:

V = u + at

5 = 65 + a (0.75)

0.75a = -60

a = -60/0.75

a = -80m/s^2

Therefore, is decelerating at 80m/s^2

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