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lesya692 [45]
3 years ago
6

A skydiver slows down from 65 m/s to 5 m/s by opening the parachute. If this

Chemistry
2 answers:
Cerrena [4.2K]3 years ago
8 0

Answer:

\boxed {\boxed {\sf D. \ 80 \ m/s^2 \ down}}

Explanation:

We are asked to find the acceleration of a skydiver. Acceleration is the change in velocity over the change in time, so the formula for calculating acceleration is:

a= \frac{v_f-v_i}{t}

The skydiver was initially traveling 65 meters per second, then he slowed down to a final velocity of 5 meters per second. He slowed down in 0.75 seconds.

\bullet \  v_f = 5 \ m/s \\\bullet \  v_i= 65 \ m/s \\\bullet \  t= 0.75 \ s

Substitute the values into the formula.

a= \frac{ 5 \ m/s - 65 \ m/s}{0.75 \ s}

Solve the numerator.

a= \frac{-60 \ m/s}{0.75 \ s}

Divide.

a= -80 \ m/s^2

The acceleration of the skydiver is <u>-80 meters per second squared</u> or <u>80 meters per second squared down</u>. The skydiver is slowing down or decelerating, so the acceleration is negative or down.

aivan3 [116]3 years ago
5 0

Answer:

D. -80m/s^2

Explanation:

V = u + at

5 = 65 + a (0.75)

0.75a = -60

a = -60/0.75

a = -80m/s^2

Therefore, is decelerating at 80m/s^2

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Nadya [2.5K]
They form chemical bonds
5 0
3 years ago
How man grams of cl2 are consumed to produce 12.0 g of KCl
Korvikt [17]

Answer:

5.71 g

Explanation:

Step 1: Write the balanced equation

2 K + Cl₂ ⇒ 2 KCl

Step 2: Calculate the moles corresponding to 12.0 g of KCl

The molar mass of KCl is 74.55 g/mol.

12.0 g × 1 mol/74.55 g = 0.161 mol

Step 3: Calculate the moles of Cl₂ needed to produce 0.161 moles of KCl

The molar ratio of Cl₂ to KCl is 1:2. The moles of Cl₂ needed are 1/2 × 0.161 mol = 0.0805 mol

Step 4: Calculate the mass corresponding to 0.0805 moles of Cl₂

The molar mass of Cl₂ is 70.91 g/mol.

0.0805 mol × 70.91 g/mol = 5.71 g

8 0
3 years ago
Acetylene gas is often used in welding torches because of the very high heat produced when it reacts with oxygen gas, producing
rodikova [14]

Answer:

0.225 mol = 0.23 mol to 2 significant figures

Explanation:

Calculate the moles of oxygen needed to produce 0.090 mol of water

The equation of the reaction is given as;

2 C2H2 + 5 O2 --> 4 CO2 + 2 H2O

From the equation of the reaction;

5 mol of O2 produces 2 mol of H2O

x mol of O2 produces 0.090 mol of H2O

5 = 2

x = 0.090

x = 0.090 * 5 / 2

x = 0.225 mol

8 0
3 years ago
Phosgene (COCl2) is a toxic substance that forms readily from carbon monoxide and chlorine at elevated temperatures: CO(g) + Cl2
lapo4ka [179]

Answer: Concentration of CO = 0.328 M

Concentration of Cl_2 = 0.328 M

Concentration of COCl_2 = 0.532 M

Explanation:

Moles of  CO and Cl_2 = 0.430 mole

Volume of solution = 0.500 L

Initial concentration of CO and Cl_2  =\frac{moles}{volume}=\frac{0.430}{0.500}=0.860M

The given balanced equilibrium reaction is,

                            CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)

Initial conc.          0.860M     0.860M           0

At eqm. conc.    (0.860-x) M  (0.860-x) M     (x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[COCl_2]}{[CO][Cl_2]}

Now put all the given values in this expression, we get :

4.95=\frac{x}{(0.860-x)^2}

By solving the term 'x', we get :

x =  0.532 M

Thus, the concentrations of CO,Cl_2\text{ and }COCl_2 at equilibrium are :

Concentration of CO = (0.860-x) M =(0.860-0.532) M = 0.328 M

Concentration of Cl_2 =  (0.860-x) M  =  (0.860-0.532) M = 0.328 M

Concentration of COCl_2 = x M = 0.532 M

3 0
3 years ago
Someone help me please please help whats the ratio of carbon and hydrogen??????? <br>​
MatroZZZ [7]

1:2

The ratio of carbon, hydrogen, and oxygen in most carbohydrates is 1:2:1. This means for every one carbon atom there are two hydrogen atoms and one...

3 0
3 years ago
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